If a group G is internal Direct product of its subgroups A, B, C, .... Z then G is isomorphic to ______.
external direct product of A, B, C... Z
In group theory, we often construct new groups from existing ones or decompose a group into simpler components. Two important concepts related to this are the internal direct product and the external direct product.
A group G is said to be the internal direct product of its subgroups \(A_1, A_2, \ldots, A_n\) if the following conditions are met:
In the question, G is the internal direct product of subgroups A, B, C, ..., Z. This means these subgroups satisfy the conditions listed above within G.
The external direct product of groups \(A_1, A_2, \ldots, A_n\) is a new group, denoted \(A_1 \times A_2 \times \cdots \times A_n\). Its elements are ordered n-tuples \((a_1, a_2, \ldots, a_n)\) where \(a_i \in A_i\). The group operation is performed component-wise:
\((a_1, a_2, \ldots, a_n)(b_1, b_2, \ldots, b_n) = (a_1b_1, a_2b_2, \ldots, a_nb_n)\)
This construction creates a new group from the given groups \(A_i\).
A fundamental theorem in group theory provides a link between these two concepts. It states that if a group G is the internal direct product of its subgroups \(A_1, A_2, \ldots, A_n\), then G is isomorphic to the external direct product of these subgroups, \(A_1 \times A_2 \times \cdots \times A_n\).
Isomorphism means there exists a bijective homomorphism between the two groups, preserving the group structure. Essentially, the two groups are structurally identical, even though one is formed by combining subgroups *within* G (internal) and the other is a new group constructed *from* the subgroups (external).
Let's evaluate the given options based on this understanding:
Therefore, a group G that is the internal direct product of its subgroups A, B, C, ..., Z is isomorphic to the external direct product of A, B, C, ..., Z.
| Concept | Description | Relationship |
|---|---|---|
| Internal Direct Product | A group G is formed by normal subgroups within itself satisfying specific conditions. | An internal direct product of subgroups is isomorphic to their external direct product. |
| External Direct Product | A new group constructed from given groups, with elements as tuples and component-wise operation. | |
| Isomorphism | A structure-preserving bijection between two groups. Isomorphic groups are considered structurally the same. | Connects internal and external direct products. |
The concept of direct products is crucial for understanding the structure of groups. The theorem connecting internal and external direct products allows us to analyze the structure of a group G by examining its subgroups (internal direct product) and relate it to a standard construction (external direct product). This is particularly useful in the classification of finite abelian groups, for example.
For a finite number of subgroups \(A_1, \ldots, A_n\), G is the internal direct product if:
The isomorphism \(G \cong A_1 \times A_2 \times \cdots \times A_n\) is given by the map \(\phi: A_1 \times \cdots \times A_n \to G\) defined by \(\phi((a_1, \ldots, a_n)) = a_1 a_2 \cdots a_n\). This map is a homomorphism because the elements from different subgroups commute (a consequence of the normal subgroup and intersection properties), and it is a bijection due to the conditions of the internal direct product.
Consider the following statements:
S 1: If a group (G, *) is of order n, and a ∈ G is such that a m= e for some integer m ≤ n, then m must divide n.
S 2: If a group (G, *) is of even order, then there must be an element a ∈ G such that a ≠ e and a * a = e
Which of the statements is (are) correctEvery element of a group G when expressed as internal Direct product of a, b, c, ... z if and only of every element is uniquely expressed as ?
The multiplicative group {1, -1, i, -i} is a cyclic group, its generators are
Given:
Statement A: All cyclic groups are an abelian group.
Statement B: The order of the cyclic group is the same as the order of its generator.
The number of generators of the cyclic group G of order 8 is