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Question

A subset H of a group (G, ∗) is a group if

The correct answer is

a ∈ H ⇒ a -1  ∈ H

Understanding Subgroups in Group Theory

In abstract algebra, a group is a set equipped with a binary operation that satisfies four conditions: closure, associativity, identity element existence, and inverse element existence. A subset H of a group (G, ∗) is called a subgroup of G if H is itself a group under the same operation ∗.

For a non-empty subset H of a group G to be a subgroup, it must satisfy the following conditions:

  • Closure Property: For all a, b ∈ H, a ∗ b ∈ H.
  • Identity Element: The identity element of G must be in H.
  • Inverse Element: For all a ∈ H, the inverse a-1 in G must also be in H. This is closure under the inverse element operation.

Alternatively, there is a single, more concise test for a non-empty subset H to be a subgroup: for all a, b ∈ H, a ∗ b-1 ∈ H. This single condition implies all three of the above (assuming H is non-empty).

Analyzing the Given Options for Subgroup Conditions

Let's look at the given options in the context of a subset H being a group (i.e., a subgroup):

  1. a, b ∈ H ⇒ a ∗ b ∈ H: This is the closure property. This is a necessary condition for H to be a group, but it is not sufficient on its own. For example, the set of natural numbers {1, 2, 3, ...} is closed under addition, but it is not a group because it lacks an identity element (0) and inverse elements.
  2. a ∈ H ⇒ a-1 ∈ H: This condition states that for every element 'a' in H, its inverse element 'a-1' (which exists in the larger group G) must also belong to H. This property, known as closure under inverses, is also a necessary condition for H to be a group. If H is a group, then by definition, every element in H must have an inverse *within* H. Since H is a subset of G, the inverse in H must be the same as the inverse in G. Thus, if H is a group, this condition must hold. While not sufficient alone (H also needs closure and identity), it's a fundamental requirement for the structure of a group.
  3. a, b ∈ H ⇒ a ∗ b-1 ∈ H: As mentioned earlier in group theory, this single condition, when combined with the fact that H is non-empty, is a standard test for H to be a subgroup. It implies both closure under the operation and the existence of identity and inverses within H. Among the choices, this is the strongest single condition that implies H is a group (assuming H is non-empty).
  4. H contains the identity element: The presence of the identity element is necessary for H to be a group, but it is not sufficient. For example, the set {0, 1} is a subset of the integers under addition (&Z, +), and it contains the identity 0, but it's not a group (e.g., it's not closed: 1+1 = 2 ∉ {0, 1}).

Considering the options, Option 2 highlights a crucial necessary property for a subset H to be a group under the inherited operation – the existence of inverses within H for all its elements. While Option 3 is the most comprehensive single test for a subgroup, Option 2 explicitly states the requirement that every element in H must have its inverse element also residing in H, a property indispensable for H to function as a group itself. Therefore, if H is a group, this condition must be met.

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Important Questions from Groups

  1. Consider the following statements:

    S 1: If a group (G, *) is of order n, and a ∈ G is such that a m= e for some integer m ≤ n, then m must divide n.

    S 2: If a group (G, *) is of even order, then there must be an element a ∈ G such that a ≠ e and a * a = e

    Which of the statements is (are) correct
  2. If a group G is internal Direct product of its subgroups A, B, C, .... Z then G is isomorphic to ______.

  3. Every element of a group G when expressed as internal Direct product of a, b, c, ... z if and only of every element is uniquely expressed as ?

  4. The multiplicative group {1, -1, i, -i} is a cyclic group, its generators are

  5. The number of generators of the cyclic group G of order 8 is

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