A subset H of a group (G, ∗) is a group if
a ∈ H ⇒ a -1 ∈ H
In abstract algebra, a group is a set equipped with a binary operation that satisfies four conditions: closure, associativity, identity element existence, and inverse element existence. A subset H of a group (G, ∗) is called a subgroup of G if H is itself a group under the same operation ∗.
For a non-empty subset H of a group G to be a subgroup, it must satisfy the following conditions:
Alternatively, there is a single, more concise test for a non-empty subset H to be a subgroup: for all a, b ∈ H, a ∗ b-1 ∈ H. This single condition implies all three of the above (assuming H is non-empty).
Let's look at the given options in the context of a subset H being a group (i.e., a subgroup):
Considering the options, Option 2 highlights a crucial necessary property for a subset H to be a group under the inherited operation – the existence of inverses within H for all its elements. While Option 3 is the most comprehensive single test for a subgroup, Option 2 explicitly states the requirement that every element in H must have its inverse element also residing in H, a property indispensable for H to function as a group itself. Therefore, if H is a group, this condition must be met.
The multiplicative group {1, -1, i, -i} is a cyclic group, its generators are
The number of generators of the cyclic group G of order 8 is
Consider the following statements:
S 1: If a group (G, *) is of order n, and a ∈ G is such that a m= e for some integer m ≤ n, then m must divide n.
S 2: If a group (G, *) is of even order, then there must be an element a ∈ G such that a ≠ e and a * a = e
Which of the statements is (are) correctIf the group (z, ∗) of all integers, where a ∗ b = a + b + 1 for all a, b ∈ z, the inverse of -2 is
In any group, the number of improper subgroups is