If a capacitor stores 0.12 C at 10 V, then its capacitance is-
0.012 F
The relationship between charge, voltage, and capacitance is: \begin{equation*} Q = C × V \end{equation*} To find the capacitance C, we can rearrange this formula: \begin{equation*} C = (Q)/(V) \end{equation*} Now, we substitute the given values of Q and V into this formula: \begin{equation*} C = (0.12 C)/(10 V) \end{equation*} Performing the division, we get: \begin{equation*} C = 0.012 Farads \end{equation*} The unit of capacitance is the Farad (F).
Important Questions from Circuit Elements
A color code of orange, orange, orange is for what ohmic value?
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Change in resistance of a conductor on increasing its length 3 times will be
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