Change in resistance of a conductor on increasing its length 3 times will be
Three times
This solution explains how the electrical resistance of a conductor changes when its length is increased. We will look at the relationship between resistance and length.
Electrical resistance is a measure of how much an object opposes the flow of electric current. It depends on several factors, including the material of the conductor, its length, and its cross-sectional area.
The formula for resistance ($R$) is given by:
R = \rho \frac{L}{A}
Where:
From the formula, we can see that resistance ($R$) is directly proportional to the length ($L$) of the conductor, assuming the resistivity ($\rho$) and cross-sectional area ($A$) remain constant.
This can be written as:
R \propto L
This proportionality means that if you increase the length of the conductor, its resistance will increase proportionally, provided other factors are unchanged.
Let's consider the initial state of the conductor:
According to the direct proportionality, we can write:
R_1 = k L_1
Where '$k$' is a constant of proportionality that includes resistivity and inverse of area (i.e., $k = \rho / A$).
Now, the length of the conductor is increased 3 times. This means the new length ($L_2$) is:
L_2 = 3 \times L_1
The new resistance ($R_2$) will be:
R_2 = k L_2
Substitute the value of $L_2$:
R_2 = k \times (3 L_1)
Rearranging the terms:
R_2 = 3 \times (k L_1)
Since we know that $R_1 = k L_1$, we can substitute this back into the equation:
R_2 = 3 \times R_1
The calculation shows that the new resistance ($R_2$) is 3 times the original resistance ($R_1$). Therefore, when the length of a conductor is increased 3 times, its resistance becomes three times its original value, assuming the cross-sectional area remains constant.
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