If A can do 20 percent of a work in 6 days, then A can complete the entire work in how many days?
30 days
Work and time problems often involve determining how long it takes for an individual or a group to complete a certain amount of work. The key is to understand the relationship between the amount of work done, the time taken, and the rate at which the work is done. In this specific problem, we are given the fraction of work done by person A in a certain number of days and asked to find the total time required to complete the entire work.
The problem states that A can do 20 percent of a work in 6 days. We want to find out how many days A takes to complete 100 percent of the work (the entire work).
We can set up a relationship based on the information given:
We assume that the rate of work is constant. This means the time taken is directly proportional to the amount of work done. If A does more work, it will take more time, and if A does less work, it will take less time, assuming the rate stays the same.
We can find out how much time it takes for A to complete 1 percent of the work.
If 20% work takes 6 days, then 1% work takes:
$$ \text{Time for 1% work} = \frac{\text{Time for 20% work}}{\text{Percentage of work}} $$
$$ \text{Time for 1% work} = \frac{6 \text{ days}}{20} $$
Now, to find the time taken to complete the entire work, which is 100 percent, we multiply the time taken for 1 percent by 100.
$$ \text{Time for 100% work} = \text{Time for 1% work} \times 100 $$
$$ \text{Time for 100% work} = \left(\frac{6}{20}\right) \times 100 \text{ days} $$
Let's perform the calculation:
$$ \text{Time for 100% work} = \frac{6 \times 100}{20} \text{ days} $$
$$ \text{Time for 100% work} = \frac{600}{20} \text{ days} $$
$$ \text{Time for 100% work} = 30 \text{ days} $$
So, A can complete the entire work in 30 days.
Alternatively, we can think of this using ratios:
Let \(T\) be the total time required to complete 100% of the work.
The ratio of work done is proportional to the ratio of time taken:
$$ \frac{\text{Work done (20%)}}{\text{Time taken (6 days)}} = \frac{\text{Total Work (100%)}}{\text{Total Time (T days)}} $$
$$ \frac{20}{6} = \frac{100}{T} $$
Now, solve for \(T\):
$$ 20 \times T = 6 \times 100 $$
$$ 20T = 600 $$
$$ T = \frac{600}{20} $$
$$ T = 30 $$
Thus, the total time required is 30 days.
| Work Done (Percentage) | Time Taken (Days) |
|---|---|
| 20% | 6 |
| 100% | ? |
Using the proportion: If 20% takes 6 days, then 100% takes \( x \) days.
$$ \frac{20}{100} = \frac{6}{x} $$
$$ 20x = 100 \times 6 $$
$$ 20x = 600 $$
$$ x = \frac{600}{20} $$
$$ x = 30 $$
The entire work will be completed in 30 days.
| Concept | Explanation |
|---|---|
| Work Rate | The amount of work done per unit of time. Often expressed as work done per day. |
| Total Work | Usually considered as 1 unit or 100%. |
| Relationship | Work = Rate × Time. If work is constant, Rate is inversely proportional to Time. If rate is constant, Work is directly proportional to Time. |
| Efficiency | Often related to the work rate. More efficient workers have higher work rates. |
This problem can be solved using the unitary method, where we first find the value for a single unit (in this case, 1% of the work) and then scale it up to find the value for the desired quantity (100% of the work).
The principle of direct proportionality is also fundamental here. When the rate of work is constant, the amount of work done is directly proportional to the time taken. This means if you double the work, you double the time; if you halve the work, you halve the time. This proportional relationship allows us to set up equations or ratios to solve the problem efficiently.
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