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Question

If a binary operation * on N is defined as a * b = a3 + b3, then-

The correct answer is * is commutative but not associative

Understanding Binary Operations on Natural Numbers

A binary operation '*' on a set A is a rule that assigns to every ordered pair (a, b) of elements in A an element in A. Here, the set is N (natural numbers), and the operation is defined as a * b = a3 + b3. We need to determine if this operation is commutative and/or associative.

Checking for Commutativity

A binary operation '*' on a set A is said to be commutative if a * b = b * a for all elements a, b ∈ A. Let's check the given operation a * b = a3 + b3 on N. For any a, b ∈ N:
  • Calculate a * b: \[a * b = a^3 + b^3\]
  • Calculate b * a: \[b * a = b^3 + a^3\]
Since addition of natural numbers is commutative, we know that a3 + b3 is always equal to b3 + a3 for all a, b ∈ N. Therefore, a * b = b * a for all a, b ∈ N. The operation * is commutative.

Checking for Associativity

A binary operation '*' on a set A is said to be associative if (a * b) * c = a * (b * c) for all elements a, b, c ∈ A. Let's check the given operation a * b = a3 + b3 on N. For any a, b, c ∈ N:
  • Calculate (a * b) * c: \[(a * b) * c = (a^3 + b^3) * c\] Now apply the definition of *: the first element is (a3 + b3) and the second element is c. \[(a^3 + b^3) * c = (a^3 + b^3)^3 + c^3\]
  • Calculate a * (b * c): \[a * (b * c) = a * (b^3 + c^3)\] Now apply the definition of *: the first element is a and the second element is (b3 + c3). \[a * (b^3 + c^3) = a^3 + (b^3 + c^3)^3\]
For the operation to be associative, we must have $(a^3 + b^3)^3 + c^3 = a^3 + (b^3 + c^3)^3$ for all a, b, c ∈ N. Let's test with specific natural numbers, for example, a=1, b=2, c=3.
  • (a * b) * c: \[(1 * 2) * 3 = (1^3 + 2^3) * 3 = (1 + 8) * 3 = 9 * 3\] \[9 * 3 = 9^3 + 3^3 = 729 + 27 = 756\]
  • a * (b * c): \[1 * (2 * 3) = 1 * (2^3 + 3^3) = 1 * (8 + 27) = 1 * 35\] \[1 * 35 = 1^3 + 35^3 = 1 + 42875 = 42876\]
Since $756 \neq 42876$, the equation $(a^3 + b^3)^3 + c^3 = a^3 + (b^3 + c^3)^3$ is not true for all a, b, c ∈ N. The operation * is not associative.

Summary of Properties

Based on the analysis:
  • The binary operation * defined as a * b = a3 + b3 on N is commutative.
  • The binary operation * defined as a * b = a3 + b3 on N is not associative.
Therefore, the operation * is commutative but not associative.
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Important Questions from Groups

  1. The multiplicative group {1, -1, i, -i} is a cyclic group, its generators are

  2. The number of generators of the cyclic group G of order 8 is

  3. A subset H of a group (G, ∗) is a group if

  4. Consider the following statements:

    S 1: If a group (G, *) is of order n, and a ∈ G is such that a m= e for some integer m ≤ n, then m must divide n.

    S 2: If a group (G, *) is of even order, then there must be an element a ∈ G such that a ≠ e and a * a = e

    Which of the statements is (are) correct
  5. If the group (z, ∗) of all integers, where a ∗ b = a + b + 1 for all a, b ∈ z, the inverse of -2 is

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