If a + b = 7 and ab = 3, then what will be the value of a2 + b2 ?
43
This problem asks for the value of $a^2 + b^2$ given the sum ($a+b$) and product ($ab$) of two numbers. We are provided with:
Our goal is to find the value of $a^2 + b^2$.
We can solve this problem by using the algebraic identity for the square of a binomial sum:
$$ (a+b)^2 = a^2 + 2ab + b^2 $$
To find $a^2 + b^2$, we can rearrange this formula. By subtracting $2ab$ from both sides, we get:
$$ a^2 + b^2 = (a+b)^2 - 2ab $$
Now, we substitute the known values of $a+b=7$ and $ab=3$ into the rearranged formula:
$$ a^2 + b^2 = (7)^2 - 2(3) $$
The calculation proceeds as follows:
So, the value of $a^2 + b^2$ is 43.
$$ a^2 + b^2 = 43 $$
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).