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Question

If a + b = 7 and ab = 3, then what will be the value of a2 + b2 ?

The correct answer is

43

Calculate a2 + b2 Value

This problem asks for the value of $a^2 + b^2$ given the sum ($a+b$) and product ($ab$) of two numbers. We are provided with:

  • $a + b = 7$
  • $ab = 3$

Our goal is to find the value of $a^2 + b^2$.

Using the Relevant Algebraic Identity

We can solve this problem by using the algebraic identity for the square of a binomial sum:

$$ (a+b)^2 = a^2 + 2ab + b^2 $$

To find $a^2 + b^2$, we can rearrange this formula. By subtracting $2ab$ from both sides, we get:

$$ a^2 + b^2 = (a+b)^2 - 2ab $$

Substituting the Given Values

Now, we substitute the known values of $a+b=7$ and $ab=3$ into the rearranged formula:

$$ a^2 + b^2 = (7)^2 - 2(3) $$

Step-by-Step Calculation

The calculation proceeds as follows:

  1. Calculate the square of the sum: $7^2 = 7 \times 7 = 49$.
  2. Calculate twice the product: $2 \times 3 = 6$.
  3. Subtract the result from step 2 from the result in step 1: $49 - 6 = 43$.

So, the value of $a^2 + b^2$ is 43.

$$ a^2 + b^2 = 43 $$

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Important Questions from Algebra

  1. In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

    I. x2 – 26x + 165 = 0

    II. y2 – 38y + 357 = 0

  2. Factorize the following:

    (x 2- 6xy + 9y 2) - 25

  3. If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that

    AP = PQ = QB, then the mid point of PQ is 

  4. If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?

  5. If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).

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