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Question

If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = 

The correct answer is
17.2

Division Relationship Explained

The question provides a division fact and asks us to find the result of a similar division problem where the numbers involved have different decimal placements.

  • Given: $2994 \div 14.5 = 172$
  • To find: $29.94 \div 1.45 = ?$

Decimal Shift Effect Analysis

Let's analyze how the dividend and divisor change from the given information to the problem we need to solve:

  • The dividend changes from $2994$ to $29.94$. This means the original dividend has been divided by $100$ (or the decimal point shifted 2 places to the left).
  • The divisor changes from $14.5$ to $1.45$. This means the original divisor has been divided by $10$ (or the decimal point shifted 1 place to the left).

We can express the division we need to solve in terms of the original numbers:

$29.94 \div 1.45 = \frac{29.94}{1.45}$

Now, let's rewrite the numerator and denominator using the original numbers:

Numerator: $29.94 = \frac{2994}{100}$

Denominator: $1.45 = \frac{14.5}{10}$

Substitute these back into the fraction:

$\frac{29.94}{1.45} = \frac{\frac{2994}{100}}{\frac{14.5}{10}}$

To simplify this complex fraction, we multiply the numerator by the reciprocal of the denominator:

$= \frac{2994}{100} \times \frac{10}{14.5}$

Rearrange the terms to group the known division:

$= \left(\frac{2994}{14.5}\right) \times \left(\frac{10}{100}\right)$

Calculation Steps

We know from the given information that $\frac{2994}{14.5} = 172$. Let's substitute this value:

$= 172 \times \left(\frac{10}{100}\right)$

Simplify the fraction $\frac{10}{100}$:

$= 172 \times \frac{1}{10}$

Now, perform the final multiplication:

$= \frac{172}{10}$

$= 17.2$

Therefore, $29.94 \div 1.45 = 17.2$.

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Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

  2. A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:

  3. A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :

  4. Consider the following statements:

    1. Distance between the longitudes becomes zero on North Pole and South Pole.

    2. Distance between the longitudes is maximum on the Equator.

    3. Number of longitudes is more than number of latitudes.

    Which of the statements given above is/are correct?

  5. One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :

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