To determine the day of the week on October 1st, 2016, given that October 2nd, 2012, was a Tuesday, we need to consider the number of days between the two dates and account for leap years.
From October 2nd, 2012, to October 2nd, 2016, there are four years. In these four years, there is one leap year (2016). Therefore, the total number of days is:
365 days/year * 3 years + 366 days (leap year) = 1461 days
Now, we need to find the remainder when 1461 is divided by 7 (since there are 7 days in a week):
1461 ÷ 7 = 208 with a remainder of 5.
A remainder of 5 indicates that October 2nd, 2016, was 5 days after Tuesday. Counting forward five days (Wednesday, Thursday, Friday, Saturday, Sunday), October 2nd, 2016, was a Sunday. Consequently, October 1st, 2016, was a Saturday.
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