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Question

Hypophosphatemia is manifested by an X-linked dominant allele.What proportion of the offsprings from a normal male and an affected heterozygous female will manifest the disease?

The correct answer is
$\frac{1}{2}$ sons and $\frac{1}{2}$ daughters

Understanding X-Linked Dominant Inheritance

Hypophosphatemia is caused by an X-linked dominant allele. This means the gene responsible is located on the X chromosome, and only one copy of the dominant allele is needed to express the trait.

Parental Genotypes

  • Normal Male: Genotype is XhY. (Xh represents the normal allele, Y is the male chromosome).
  • Affected Heterozygous Female: Genotype is XHXh. (XH represents the dominant disease allele, Xh represents the normal allele).

Punnett Square Analysis

We can predict the offspring genotypes using a Punnett square:

Xh Y
XH XHXh (Affected Female) XHY (Affected Male)
Xh XhXh (Normal Female) XhY (Normal Male)

Offspring Phenotypes

Analyzing the Punnett square results:

  • Daughters (XX): Inherit one X from the father (Xh) and one from the mother (XH or Xh).
    • XHXh: Affected (1 out of 2 daughters)
    • XhXh: Normal (1 out of 2 daughters)
  • Sons (XY): Inherit the Y from the father and one X from the mother (XH or Xh).
    • XHY: Affected (1 out of 2 sons)
    • XhY: Normal (1 out of 2 sons)

Therefore, $\frac{1}{2}$ of the daughters and $\frac{1}{2}$ of the sons will manifest the disease.

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Important Questions from Mendelian Inheritance

  1. Mendel's 'law of segregation' applies to the segregation of __________ during gamete formation.
  2. Fabry disease in humans is a X-linked disease. The probability (in percentage) for a phenotypically normal father and a carrier mother to have a son with Fabry disease is ________.
  3. The allele associated with albinism in humans is recessive ($c$). The probability that an albino male ($cc$) and a carrier female ($Cc$) will have an offspring with normal skin pigmentation is _________. 

    (Round off to one decimal place)

  4. The blood group of the mother is A⁺ and that of the father is AB⁺. Which of the following statements is/are correct?
  5. Assuming independent assortment and no recombination, the number of different combinations of maternal and paternal chromosomes in gametes of an organism with a diploid number of 12 is ________.
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