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Question

Hydrolysis of trans - [COLCI(en)2]+ (L = \(\mathrm{NO}_2^-\), NCS-, OH-, CI-) results in a product (A). The tendency to form cis - isomer of the product (A) follows the order

The correct answer is

L = \(\mathrm{NO}_2^-\) < CI < NCS- < OH

Hydrolysis of trans-[CoLCl(en)₂]⁺

The question asks about the hydrolysis of a coordination complex, specifically trans-[CoLCl(en)₂]⁺, where 'en' represents ethylenediamine, a bidentate ligand, and L is one of the given ligands ($\mathrm{NO}_2^-$, $\mathrm{NCS}^-$, $\mathrm{OH}^-$, $\mathrm{Cl}^-$). Hydrolysis in this context means the replacement of a ligand by a water molecule.

The starting complex is trans-[CoLCl(en)₂]⁺. This means the ligand L is positioned directly opposite (trans to) the chloride (Cl⁻) ligand. The hydrolysis reaction involves the replacement of the chloride ligand by water, likely followed by deprotonation of the coordinated water to form a hydroxyl (OH⁻) ligand, resulting in the product (A), which is [CoL(OH)(en)₂]⁺.

trans-[CoLCl(en)₂]⁺ + H₂O \(\rightarrow\) [CoL(\(\mathrm{H}_2\mathrm{O}\))(en)₂]²⁺ + Cl⁻

[CoL(\(\mathrm{H}_2\mathrm{O}\))(en)₂]²⁺ \(\rightarrow\) [CoL(OH)(en)₂]⁺ + H⁺

The product (A) is [CoL(OH)(en)₂]⁺. Since the starting material was trans, one might expect the product to be trans as well if the substitution occurred with complete retention of configuration. However, substitution reactions in octahedral Co(III) complexes often proceed via dissociative or interchange mechanisms involving 5-coordinate intermediates, which can lead to isomerization. This means that starting from a trans complex, both trans and cis isomers of the product can be formed.

The question asks about the tendency to form the cis isomer of the product (A). This tendency is influenced by the nature of the ligand L, which is trans to the leaving group (Cl⁻) in the starting material.

Factors Influencing Cis Isomer Formation

The stereochemical outcome of substitution reactions in Co(III) complexes is complex and influenced by several factors, including the nature of the leaving group, the incoming group, and the non-leaving ligands (like L and en in this case). The trans effect, well-known for square planar Pt(II) complexes, predicts the lability of the ligand trans to a given ligand. While Co(III) complexes don't exhibit as strong a trans effect, the influence of the trans ligand (L) on the substitution rate and stereochemistry is still significant.

Studies on Co(III) amine complexes have shown that the degree of isomerization from trans to cis during substitution reactions can be related to the electronic properties of the ligand L that is trans to the leaving group. Generally, ligands that are better electron donors or weaker pi-acceptors can promote greater isomerization towards the cis product. This effect is thought to be related to how the ligand L influences the stability or geometry of the 5-coordinate intermediate formed after the departure of the leaving group (Cl⁻), facilitating rearrangement to a configuration that favors the formation of the cis isomer upon attack by the incoming water molecule.

Ordering Ligands by Tendency to Form Cis

Let's consider the electronic nature of the given ligands L:

  • \(\mathrm{NO}_2^-\): Can coordinate via N or O. Usually coordinates via N to Co(III) (nitro). It is a moderate sigma donor and a good pi-acceptor.
  • \(\mathrm{NCS}^-\): Can coordinate via N or S. Usually coordinates via N to Co(III) (isothiocyanato). It is a sigma donor and has some pi-acceptor character (weaker than \(\mathrm{NO}_2^-\)).
  • \(\mathrm{OH}^-\): A strong sigma donor and a strong pi-donor.
  • \(\mathrm{Cl}^-\): A sigma donor and a pi-donor. Pi-donation is generally weaker than \(\mathrm{OH}^-\).

Based on the idea that stronger electron donation by L or weaker pi-acceptor character of L favors cis product formation, we can arrange these ligands. \(\mathrm{OH}^-\) is the strongest electron donor (sigma and pi). \(\mathrm{Cl}^-\) is a significant donor (sigma and pi). \(\mathrm{NCS}^-\) and \(\mathrm{NO}_2^-\) are sigma donors but also pi-acceptors. \(\mathrm{NO}_2^-\) is typically a stronger pi-acceptor than \(\mathrm{NCS}^-\) (via N bonding).

Order of increasing electron donation / decreasing pi-acceptor character (approximate):

\(\mathrm{NO}_2^-\) (weakest donor/strongest acceptor) < \(\mathrm{Cl}^-\) (donor, pi-donor) < \(\mathrm{NCS}^-\) (donor, weaker acceptor) < \(\mathrm{OH}^-\) (strongest donor)

Based on this trend, the tendency to form the cis isomer should increase in the order of increasing electron donation by L.

Therefore, the order of the tendency to form the cis isomer of product (A) is expected to be:

L = \(\mathrm{NO}_2^-\) < \(\mathrm{Cl}^-\) < \(\mathrm{NCS}^-\) < \(\mathrm{OH}^-\)

This order means that when L is \(\mathrm{NO}_2^-\), the hydrolysis of trans-[Co(\(\mathrm{NO}_2\))Cl(en)₂]⁺ results in the lowest tendency to form the cis isomer of [Co(\(\mathrm{NO}_2\))(OH)(en)₂]⁺. When L is \(\mathrm{OH}^-\), the hydrolysis of trans-[Co(OH)Cl(en)₂]⁺ results in the highest tendency to form the cis isomer of [Co(OH)₂(en)₂]⁺.

Comparing this derived order with the provided options, we find a match.

The tendency to form cis - isomer of the product (A) follows the order:

L = \(\mathrm{NO}_2^-\) < \(\mathrm{Cl}^-\) < \(\mathrm{NCS}^-\) < \(\mathrm{OH}^-\)

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Important Questions from Coordination Compounds

  1. Which soft metal in group 1 of the periodic table tarnishes within a few seconds of exposure to air?

  2. Which of the following compound is paramagnetic?

  3. The chemical formula of sodium nitroprusside is

  4. Catalyst used in Haber-Bosch process for making NH3 is __________.

  5. The red color of oxy-haemoglobin is mainly due to ________.

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