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Question

Consider the following reaction:

Hg2+ (aq) + X- (aq) = [HgX]+(aq).

The stability constants for [HgX]+ (aq) for X = F, Cl and Br follow the order

The correct answer is

F < Cl < Br

Stability of Hg2+ Halide Complexes

The reaction given is the formation of a complex ion between the metal ion $Hg^{2+}(aq)$ and a halide ion $X^{-}(aq)$: $$Hg^{2+} (aq) + X^{-} (aq) \rightleftharpoons [HgX]^{+}(aq)$$

The stability of this complex ion is quantified by its stability constant, $\beta_1$, which is defined as:

$$\beta_1 = \frac{[[HgX]^{+}]}{[Hg^{2+}][X^{-}]}$$

A higher value of $\beta_1$ indicates a more stable complex.

Factors Affecting Complex Stability

The stability of complexes formed between metal ions and ligands is influenced by various factors. One important concept for predicting stability, especially with metal ions like $Hg^{2+}$, is the Hard-Soft Acid-Base (HSAB) principle.

  • Acids (metal ions) and bases (ligands) are classified as hard or soft based on their polarizability, size, and charge density.
  • Hard acids are typically small, highly charged metal ions with low polarizability (e.g., $Li^{+}$, $Na^{+}$, $K^{+}$, $Mg^{2+}$, $Ca^{2+}$, $Al^{3+}$, $Ti^{4+}$). They prefer to bond with hard bases, which are small, less polarizable ligands with high charge density (e.g., $F^{-}$, $OH^{-}$, $H_2O$, $NH_3$ as a hard base).
  • Soft acids are typically larger, less highly charged or polarizable metal ions, often with easily deformable electron clouds (e.g., $Cu^{+}$, $Ag^{+}$, $Au^{+}$, $Cd^{2+}$, $Hg^{2+}$, $Pb^{2+}$). They prefer to bond with soft bases, which are larger, more polarizable ligands with diffuse electron clouds (e.g., $I^{-}$, $S^{2-}$, $CN^{-}$, $CO$).

Applying HSAB Principle to Hg2+ and Halides

$Hg^{2+}$ is known as a soft acid due to its large size and d¹⁰ electron configuration, which makes its electron cloud relatively polarizable.

The halide ions $F^{-}$, $Cl^{-}$, and $Br^{-}$ act as ligands ($X^-$). Let's consider their characteristics:

  • $F^{-}$: Smallest halide, highest electronegativity, low polarizability. Classified as a hard base.
  • $Cl^{-}$: Larger than $F^{-}$, lower electronegativity, more polarizable than $F^{-}$. Classified as a borderline base.
  • $Br^{-}$: Larger than $Cl^{-}$, lower electronegativity, even more polarizable than $Cl^{-}$. Classified as a soft base.

The order of softness of these halide bases is $F^{-} < Cl^{-} < Br^{-}$.

Stability Order Prediction

According to the HSAB principle, a soft acid like $Hg^{2+}$ will form more stable complexes with soft bases compared to hard bases. Since the softness of the halide ligands increases in the order $F^{-} < Cl^{-} < Br^{-}$, the stability of the complexes $[HgX]^+$ is expected to increase in the same order.

Therefore, the stability constants $\beta_1$ for the complexes $[HgF]^+$, $[HgCl]^+$, and $[HgBr]^+$ will follow the order:

$$\beta_1([HgF]^{+}) < \beta_1([HgCl]^{+}) < \beta_1([HgBr]^{+})$$

This means the stability order for $X=F, Cl,$ and $Br$ is $F < Cl < Br$.

Conclusion

Based on the HSAB principle, the soft acid $Hg^{2+}$ forms increasingly stable complexes with halide ligands as their softness increases. The softness of halide ions increases from $F^{-}$ to $Cl^{-}$ to $Br^{-}$. Hence, the stability constants for the complexes $[HgX]^+(aq)$ follow the order $F < Cl < Br$.

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Important Questions from Coordination Compounds

  1. Which soft metal in group 1 of the periodic table tarnishes within a few seconds of exposure to air?

  2. Which of the following compound is paramagnetic?

  3. The chemical formula of sodium nitroprusside is

  4. Catalyst used in Haber-Bosch process for making NH3 is __________.

  5. The red color of oxy-haemoglobin is mainly due to ________.

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