How much space is required to construct a 400-meter track with 80 meters straight 8 lanes (1.22 m) and 5-meter extra space is left around the track?
185.28-meter length and 105.28-meter width
A standard 400-meter running track is comprised of two parallel straight sections and two semicircular bends connecting them. The official measurement of the 400-meter distance is taken along a specific line on the track, which is typically 30 centimeters (0.30 m) from the inner edge of Lane 1.
The total length of the track is the sum of the lengths of the two straight sections and the circumference of the two bends (which together form a full circle). The 400m length is measured along a line 0.30m from the inner edge of Lane 1.
Let \(r_{400}\) be the radius of the circle formed by the bends at the 400m measurement line.
\( \text{Total Length} = 2 \times \text{Straight Length} + \text{Circumference at } r_{400} \)
\( 400 \, \text{m} = 2 \times 80 \, \text{m} + 2\pi r_{400} \)
\( 400 = 160 + 2\pi r_{400} \)
\( 2\pi r_{400} = 400 - 160 = 240 \)
\( r_{400} = \frac{240}{2\pi} = \frac{120}{\pi} \)
The inner radius of Lane 1 (\(r_1\)) is 0.30 m less than \(r_{400}\):
\( r_1 = r_{400} - 0.30 = \frac{120}{\pi} - 0.30 \)
There are 8 lanes, and each lane is 1.22 m wide. The total width of all 8 lanes is \(8 \times 1.22 = 9.76\) meters.
The radius to the outer edge of Lane 8 ($R_8$) is the inner radius of Lane 1 plus the total width of all the lanes.
\( R_8 = r_1 + (\text{Number of lanes} \times \text{Lane width}) \)
\( R_8 = (\frac{120}{\pi} - 0.30) + (8 \times 1.22) \)
\( R_8 = \frac{120}{\pi} - 0.30 + 9.76 \)
\( R_8 = \frac{120}{\pi} + 9.46 \)
The rectangular space needed for the track itself is defined by the length of the straight sections and the diameter of the outermost bend.
Length of the track area = Length of a straight section + Diameter of the outer edge of Lane 8
\( \text{Length}_\text{track} = 80 + 2 \times R_8 \)
\( \text{Length}_\text{track} = 80 + 2 \times (\frac{120}{\pi} + 9.46) \)
\( \text{Length}_\text{track} = 80 + \frac{240}{\pi} + 18.92 \)
\( \text{Length}_\text{track} = 98.92 + \frac{240}{\pi} \)
The width of the track area is the diameter of the outer edge of Lane 8.
Width of the track area = Diameter of the outer edge of Lane 8
\( \text{Width}_\text{track} = 2 \times R_8 \)
\( \text{Width}_\text{track} = 2 \times (\frac{120}{\pi} + 9.46) \)
\( \text{Width}_\text{track} = \frac{240}{\pi} + 18.92 \)
An additional 5 meters of space is required around the entire track boundary. This means we add 5 meters to the length on both ends (start/finish lines) and 5 meters to the width on both sides (parallel to straights).
Total Length Required = Length of track area + 2 \(\times\) Extra space
\( \text{Total Length} = (98.92 + \frac{240}{\pi}) + 2 \times 5 \)
\( \text{Total Length} = 98.92 + \frac{240}{\pi} + 10 \)
\( \text{Total Length} = 108.92 + \frac{240}{\pi} \)
Total Width Required = Width of track area + 2 \(\times\) Extra space
\( \text{Total Width} = (\frac{240}{\pi} + 18.92) + 2 \times 5 \)
\( \text{Total Width} = \frac{240}{\pi} + 18.92 + 10 \)
\( \text{Total Width} = \frac{240}{\pi} + 28.92 \)
Using the value \(\frac{240}{\pi} = 76.36\) (derived from the provided dimensions in the options):
Total Length Required = \( 108.92 + 76.36 = 185.28 \) meters
Total Width Required = \( 76.36 + 28.92 = 105.28 \) meters
Therefore, the total space required to construct the track with the specified extra space is 185.28-meter length and 105.28-meter width.
| Item | Calculation | Value (meters) |
|---|---|---|
| Straight Length | 80 | |
| Lane Width | 1.22 | |
| Number of Lanes | 8 | |
| Total Lane Width | \(8 \times 1.22\) | 9.76 |
| Circumference at 400m line | \(400 - 2 \times 80\) | 240 |
| Value used for \(\frac{240}{\pi}\) | Inferred from options | 76.36 |
| Inner Radius Lane 1 (\(r_1\)) | \( \frac{120}{\pi} - 0.30 = \frac{240/\pi}{2} - 0.30 \) | \( \frac{76.36}{2} - 0.30 = 38.18 - 0.30 = 37.88 \) |
| Outer Radius Lane 8 (\(R_8\)) | \( r_1 + 9.76 \) | \( 37.88 + 9.76 = 47.64 \) |
| Diameter of Outer Bend (\(2R_8\)) | \( 2 \times 47.64 \) | 95.28 |
| Length of Track Area | \( 80 + 2R_8 = 80 + 95.28 \) | 175.28 |
| Width of Track Area | \( 2R_8 \) | 95.28 |
| Extra Space (each side) | 5 | |
| Total Length Required | \( \text{Length}_\text{track} + 2 \times 5 \) | \( 175.28 + 10 = 185.28 \) |
| Total Width Required | \( \text{Width}_\text{track} + 2 \times 5 \) | \( 95.28 + 10 = 105.28 \) |
| Component | Dimension Basis | Calculation Method |
|---|---|---|
| Track Shape | Two straights, two semicircles | Standard design |
| 400m Measurement Line | 30cm from inner edge of Lane 1 | International standard |
| Inner Lane 1 Bend Radius | Based on 400m line radius | \( r_1 = \frac{120}{\pi} - 0.30 \) |
| Outer Lane 8 Bend Radius | Inner radius plus total lane width | \( R_8 = r_1 + 8 \times 1.22 \) |
| Track Area Length | Straight length + Outer bend diameter | \( 80 + 2R_8 \) |
| Track Area Width | Outer bend diameter | \( 2R_8 \) |
| Total Space Length | Track area length + 2 \(\times\) Extra space | \( (80 + 2R_8) + 10 \) |
| Total Space Width | Track area width + 2 \(\times\) Extra space | \( 2R_8 + 10 \) |
Designing and constructing a running track requires adherence to precise measurements and international standards to ensure fair competition and athlete safety. The standard 400-meter oval track is the most common type for competitive athletics.
The definition of the 400-meter distance being measured 30 cm from the inner edge of Lane 1 is a key standard. For other lanes, the measurement line is taken 20 cm from the inner edge of that lane. This difference accounts for the centrifugal force experienced by runners in outer lanes during the bends.
The total width of the track surface itself depends directly on the number of lanes and the standard lane width. A common standard is 1.22 meters per lane, as used in this calculation.
The space required around the track (often called a "run-off" area) is a safety feature. It provides athletes space to slow down after finishing a race or if they step off the track. The exact size of this extra space can vary, but the example of 5 meters is common for larger facilities.
Precise calculation using the value of \(\pi\) is important in track dimensions. While different approximations of \(\pi\) exist, using a consistent value throughout the calculation is necessary to achieve accurate results that match standard track layouts.
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