How many times do the hour hand and the minute hand of a clock coincide in a day?
22
This question asks how many times the hour hand and the minute hand of a standard analog clock meet or coincide within a 24-hour period, which is considered a day.
To solve this classic clock problem, we need to understand the relative movement of the two hands.
Let's first determine the speed of each hand in degrees per minute:
For the hands to coincide, the faster minute hand must "catch up" to the slower hour hand. The difference in their speeds is the relative speed:
Relative Speed = Speed of Minute Hand - Speed of Hour Hand
Relative Speed = $6^\circ/\text{minute} - 0.5^\circ/\text{minute} = 5.5^\circ/\text{minute}$.
The hands coincide every time the minute hand gains a full 360 degrees on the hour hand. The time taken for the minute hand to gain 360 degrees is:
Time for coincidence = $\frac{360^\circ}{\text{Relative Speed}} = \frac{360^\circ}{5.5^\circ/\text{minute}} = \frac{360}{11/2} \text{ minutes} = \frac{720}{11} \text{ minutes}$.
This means the hands coincide approximately every 65.45 minutes.
In a 12-hour period, there are $12 \times 60 = 720$ minutes. If they coincided exactly every 60 minutes, they would meet 12 times. However, since the interval is slightly longer ($\frac{720}{11}$ minutes), they meet less than 12 times in 12 hours.
The number of times they coincide in 12 hours is:
Number of coincidences = $\frac{\text{Total minutes in 12 hours}}{\text{Time per coincidence}} = \frac{720 \text{ minutes}}{720/11 \text{ minutes/coincidence}} = 11 \text{ times}$.
The reason it's 11 and not 12 is that the coincidence that would theoretically occur between 11:00 and 12:00 happens exactly at 12:00. So, in the interval from 12:00 to 12:00, you have coincidences at 12:00, and then 10 more times scattered between the hours (roughly at 1:05, 2:11, ..., 10:55).
A day consists of 24 hours, which is two 12-hour cycles.
The coincidence at 12:00 PM (noon) is distinct from the coincidence at 12:00 AM (midnight). Therefore, in a full 24-hour period (e.g., from 00:00 to 24:00), the total number of times the hour and minute hands coincide is the sum of the coincidences in the two 12-hour periods:
Total coincidences in 24 hours = 11 (first 12 hours) + 11 (second 12 hours) = 22 times.
The hands coincide 22 times in a day.
| Time Period | Description | Number of Coincidences |
|---|---|---|
| 12 Hours | e.g., 12 AM to 12 PM | 11 times |
| 24 Hours | 1 Day (e.g., 12 AM to 12 AM next day) | 22 times |
| Relative Position | Angle | Frequency in 12 Hrs | Frequency in 24 Hrs |
|---|---|---|---|
| Coinciding (Overlap) | 0° | 11 times | 22 times |
| Opposite Direction | 180° | 11 times | 22 times |
| Right Angle | 90° | 22 times | 44 times |
It's a common misunderstanding that the hands coincide 24 times in 24 hours. The key point of exception is the 12 o'clock mark. In a 12-hour cycle, the hands align at 12:00. The alignment that would typically occur between 11 and 12 does not happen within that hour interval; it occurs exactly at 12:00, which also serves as the alignment point for the 12-1 interval. This means the coincidence around 12 o'clock is 'shared' between two intervals, effectively reducing the count by one in each 12-hour period, leading to 11 coincidences per 12 hours and thus 22 coincidences in 24 hours.
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