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Question

How many three-digit even numbers can be formed using the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

The correct answer is
108

Forming Three-Digit Even Numbers Using Digits 1-6

This problem involves finding the total count of three-digit numbers that meet specific criteria: they must be even, and they must be formed using the digits {1, 2, 3, 4, 5, 6}. Crucially, the digits can be repeated.

Understanding the Constraints

We need to form a three-digit number. Let's represent the positions as Hundreds, Tens, and Units.

  • Available Digits: {1, 2, 3, 4, 5, 6} (Total 6 digits).
  • Repetition: Allowed. This means the same digit can be used multiple times in the number.
  • Even Number Condition: For a number to be even, its units digit must be an even number.

Identifying Choices for Each Digit

We need to determine the number of possible choices for each of the three positions (hundreds, tens, and units) based on the given constraints.

  1. Units Place:

    The number must be even. The available digits are {1, 2, 3, 4, 5, 6}. The even digits in this set are {2, 4, 6}. Therefore, there are 3 possible choices for the units place.

  2. Hundreds Place:

    Since repetition is allowed, any of the available 6 digits ({1, 2, 3, 4, 5, 6}) can be placed in the hundreds position. Thus, there are 6 possible choices.

  3. Tens Place:

    Similarly, because repetition is allowed, any of the 6 available digits ({1, 2, 3, 4, 5, 6}) can be used for the tens place. This gives us 6 possible choices.

Calculating the Total Number of Three-Digit Even Numbers

To find the total number of three-digit even numbers that can be formed, we apply the fundamental principle of counting (multiplication principle). We multiply the number of choices for each position:

Total Numbers = (Choices for Hundreds Place) $\times$ (Choices for Tens Place) $\times$ (Choices for Units Place)

Using LaTeX for the calculation:

$$ \text{Total Numbers} = 6 \times 6 \times 3 $$

Performing the multiplication:

$$ 6 \times 6 = 36 $$

$$ 36 \times 3 = 108 $$

Final Result

Therefore, there are 108 possible three-digit even numbers that can be formed using the digits 1, 2, 3, 4, 5, 6 when repetition of digits is allowed.

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Important Questions from Fundamental Principles of Counting

  1. What is the number of four digit decimal number (<1) in which no digit is repeated?

  2. Let S = {2, 3, 4, 5, 6, 7, 9}. How many different 3-digit numbers (with all digits different) from S can be made which are less than 500?

  3. Consider the digits 3, 5, 7, 9. What is the number of 5-digit numbers formed by these digits in which each of these four digits appears?

  4. 3-digit numbers are formed using the digits 1, 3, 7 without repetition of digits. A number is randomly selected. What is the probability that the number is divisible by 3?

  5. Consider the following paragraph:

    THE ABILITY TO REASON ACCURATELY IS VERY IMPORTANT, AS IS THE ABILITY TO COUNT. AS AN EXERCISE IN BOTH, LET US COUNT HOW MANY TIMES THE LETTER "E" OCCURS IN THIS PARAGRAPH. THE CORRECT COUNT IS ________.

    Which option when put in the blank in the above paragraph will make the final sentence accurate?

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