The task is to find pairs of letters within the word 'COMFORTS' where the number of letters separating them in the word is equal to the number of letters separating them in the English alphabet. This analysis must cover both forward (left-to-right) and backward (right-to-left) directions.
We represent the word 'COMFORTS' with letter positions (0-indexed) and their corresponding alphabetical values (A=1, B=2, etc.).
| Letter | C | O | M | F | O | R | T | S |
| Position (0-indexed) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Alphabetical Value (A=1) | 3 | 15 | 13 | 6 | 15 | 18 | 20 | 19 |
We look for letter pairs (letter at index $i$, letter at index $j$) where $i < j$ such that the absolute difference in their alphabetical values equals the number of letters between them in the word ($j - i - 1$).
Total pairs in the forward direction: 2.
We look for letter pairs (letter at index $i$, letter at index $j$) where $i > j$ such that the absolute difference in their alphabetical values equals the number of letters between them in the word ($i - j - 1$).
Total pairs in the backward direction: 2.
The total count is the sum of pairs found in both directions.
Total Pairs = (Forward Pairs) + (Backward Pairs) = 2 + 2 = 4.
There are 4 such pairs of letters in the word COMFORTS.
Select the term that will come next in the following series.
$1O5$, $1P6$, $1Q7$, __________
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i. flower
ii. sprout
iii. fruit
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v. seed
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Select the option that can replace the question mark (?) in the following series.
BH14, CJ17, DL20, EN23, ?