Refer to the following series and answer the question. (Counting to be done from left to right only.) (All numbers are single-digit numbers only.) (Left) 5 4 3 1 6 8 8 1 5 7 7 7 4 1 6 2 7 9 1 3 9 7 7 3 9 2 6 (Right) How many such odd numbers are there, each of which is immediately preceded by an odd number and also immediately followed by an even number?
3
We scan the sequence and check each odd digit to see whether its left neighbour is odd and its right neighbour is even.
At position 4 the digit is 1 (odd); left neighbour is 3 (odd), right neighbour is 6 (even). This qualifies.
At position 12 the digit is 7 (odd); left neighbour is 7 (odd), right neighbour is 4 (even). This qualifies.
At position 25 the digit is 9 (odd); left neighbour is 3 (odd), right neighbour is 2 (even). This qualifies.
Every other odd digit in the row either has an even predecessor or an odd successor, so no further case fits both rules.
Hence, the required count is 3.
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