Given the following information, calculate the dry adiabatic lapse rate in Jupiter’s atmosphere.Composition Specific heat Acceleration
due to gravity$\text{H}_2$ $13000\ \text{J/kg/K}$ $26\ \text{m/s}^2$
The dry adiabatic lapse rate ($\Gamma_d$) is the rate at which the temperature of a parcel of dry air decreases as it rises through the atmosphere under adiabatic conditions. It can be calculated using the acceleration due to gravity ($g$) and the specific heat capacity at constant pressure ($c_p$).
The formula used is:
$ \Gamma_d = \frac{g}{c_p} $
Where:
This formula yields the lapse rate in Kelvin per meter (K/m).
We are given the following information for Jupiter:
Substitute these values into the formula:
$ \Gamma_d = \frac{26 \ \text{m/s}^2}{13000 \ \text{J/kg/K}} $
To perform the calculation, note the unit relationship: $1 \ \text{J} = 1 \ \text{kg} \cdot \text{m}^2/\text{s}^2$. Therefore, the units of $c_p$ are equivalent to $\text{m}^2/(\text{s}^2 \cdot \text{K})$.
$ \Gamma_d = \frac{26 \ \text{m/s}^2}{13000 \ \text{m}^2/(\text{s}^2 \cdot \text{K})} $
$ \Gamma_d = \frac{26}{13000} \ \text{K/m} $
$ \Gamma_d = 0.002 \ \text{K/m} $
The question asks for the answer in degrees Celsius per kilometer (°C/km). We need to convert K/m to °C/km.
Unit Conversion Factors:
Apply these conversion factors:
$ \Gamma_d = 0.002 \ \frac{\text{K}}{\text{m}} \times \frac{1 \ \text{°C}}{1 \ \text{K}} \times \frac{1000 \ \text{m}}{1 \ \text{km}} $
$ \Gamma_d = 0.002 \times 1000 \ \text{°C/km} $
$ \Gamma_d = 2 \ \text{°C/km} $
The dry adiabatic lapse rate in Jupiter's atmosphere, based on the given values, is 2 °C/km.
| Distance from the Sun | Radius of the planet | Incident Solar flux density | Equivalent temperature | |
| Planet A | $d_1$ | $r_1$ | $F_1$ | $T_1$ |
| Planet B | $d_2 = 4d_1$ | $r_2 = 2r_1$ | $F_2$ | $T_2$ |