The solar constant ($F$) represents the solar radiation flux received per unit area at a specific distance ($D$) from the Sun. According to the inverse square law, the intensity of radiation from a point source like the Sun decreases proportionally to the square of the distance from the source.
Mathematically, this relationship is expressed as:
$F \propto \frac{1}{D^2}$
The radii of the planets do not affect the value of the solar constant itself, as it's defined as flux per unit area at that distance.
We are given:
Using the inverse square law:
$F_{\text{SA}} \propto \frac{1}{d^2}$
$F_{\text{SB}} \propto \frac{1}{(2d)^2} = \frac{1}{4d^2}$
To find the relationship between $F_{\text{SA}}$ and $F_{\text{SB}}$, we can take the ratio:
$\frac{F_{\text{SA}}}{F_{\text{SB}}} = \frac{1/d^2}{1/(4d^2)}$
Simplifying the expression:
$\frac{F_{\text{SA}}}{F_{\text{SB}}} = \frac{1}{d^2} \times \frac{4d^2}{1} = 4$
Therefore, the relationship is:
$F_{\text{SA}} = 4F_{\text{SB}}$
| Distance from the Sun | Radius of the planet | Incident Solar flux density | Equivalent temperature | |
| Planet A | $d_1$ | $r_1$ | $F_1$ | $T_1$ |
| Planet B | $d_2 = 4d_1$ | $r_2 = 2r_1$ | $F_2$ | $T_2$ |
A planet of radius $r$ has a core of radius $r_c$ and a mantle. It has no crust. Its mean density is $\rho$ and the density of its core is $\rho_c$. What is the density of the mantle?