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Question

A planet of radius $r$ has a core of radius $r_c$ and a mantle. It has no crust. Its mean density is $\rho$ and the density of its core is $\rho_c$. What is the density of the mantle?

The correct answer is
$\frac{\rho - \left(\frac{r_c}{r}\right)^3\rho_c}{1-\left(\frac{r_c}{r}\right)^3}$

Calculating Planet Mantle Density

The mean density ($\rho$) of the planet is the total mass divided by the total volume. The planet consists of a core and a mantle. We need to find the density of the mantle ($\rho_m$).

Planet Composition and Volumes

The planet has a core of radius $r_c$ and a mantle extending to radius $r$. The total volume ($V$) of the planet is the volume of a sphere with radius $r$, and the core volume ($V_c$) is the volume of a sphere with radius $r_c$. The mantle volume ($V_m$) is the difference between the total volume and the core volume.

  • Total Volume: $V = \frac{4}{3}\pi r^3$
  • Core Volume: $V_c = \frac{4}{3}\pi r_c^3$
  • Mantle Volume: $V_m = V - V_c = \frac{4}{3}\pi r^3 - \frac{4}{3}\pi r_c^3 = \frac{4}{3}\pi (r^3 - r_c^3)$

Mass Calculation

The mass of each part is its density multiplied by its volume.

  • Mass of Core: $M_c = \rho_c V_c = \rho_c \left(\frac{4}{3}\pi r_c^3\right)$
  • Mass of Mantle: $M_m = \rho_m V_m = \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)$
  • Total Mass: $M = M_c + M_m = \rho_c \left(\frac{4}{3}\pi r_c^3\right) + \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)$

Deriving Mantle Density

Using the definition of mean density, $\rho = \frac{M}{V}$, we can set up the equation:

$ \rho = \frac{\rho_c \left(\frac{4}{3}\pi r_c^3\right) + \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)}{\frac{4}{3}\pi r^3} $

Cancel the common factor $\frac{4}{3}\pi$:

$ \rho = \frac{\rho_c r_c^3 + \rho_m (r^3 - r_c^3)}{r^3} $

Multiply both sides by $r^3$:

$ \rho r^3 = \rho_c r_c^3 + \rho_m (r^3 - r_c^3) $

Rearrange to solve for $\rho_m (r^3 - r_c^3)$:

$ \rho_m (r^3 - r_c^3) = \rho r^3 - \rho_c r_c^3 $

Finally, isolate $\rho_m$:

$ \rho_m = \frac{\rho r^3 - \rho_c r_c^3}{r^3 - r_c^3} $

Divide the numerator and denominator by $r^3$ to match the option format:

$ \rho_m = \frac{\rho - \rho_c \frac{r_c^3}{r^3}}{1 - \frac{r_c^3}{r^3}} = \frac{\rho - \left(\frac{r_c}{r}\right)^3\rho_c}{1-\left(\frac{r_c}{r}\right)^3} $

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Important Questions from Planetary Bodies

  1. The correct sequence of planets in order of increasing surface temperature is:
  2. Atmosphere of planet Mars is almost entirely made up of $\text{CO}_2$. But the surface temperature of Mars is less than that of the Earth because:
  3. Consider two planets A and B with radii $2r$ and $r$, respectively. Let their distances from the Sun be $d$ and $2d$, respectively. The solar constants for A ($F_{\text{SA}}$) and B ($F_{\text{SB}}$) are related by
  4. Given the following information, calculate the dry adiabatic lapse rate in Jupiter’s atmosphere.

    CompositionSpecific heatAcceleration
    due to gravity
    $\text{H}_2$$13000\ \text{J/kg/K}$$26\ \text{m/s}^2$
  5. Mercury has no known natural satellite because of its
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