A planet of radius $r$ has a core of radius $r_c$ and a mantle. It has no crust. Its mean density is $\rho$ and the density of its core is $\rho_c$. What is the density of the mantle?
The mean density ($\rho$) of the planet is the total mass divided by the total volume. The planet consists of a core and a mantle. We need to find the density of the mantle ($\rho_m$).
The planet has a core of radius $r_c$ and a mantle extending to radius $r$. The total volume ($V$) of the planet is the volume of a sphere with radius $r$, and the core volume ($V_c$) is the volume of a sphere with radius $r_c$. The mantle volume ($V_m$) is the difference between the total volume and the core volume.
The mass of each part is its density multiplied by its volume.
Using the definition of mean density, $\rho = \frac{M}{V}$, we can set up the equation:
$ \rho = \frac{\rho_c \left(\frac{4}{3}\pi r_c^3\right) + \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)}{\frac{4}{3}\pi r^3} $
Cancel the common factor $\frac{4}{3}\pi$:
$ \rho = \frac{\rho_c r_c^3 + \rho_m (r^3 - r_c^3)}{r^3} $
Multiply both sides by $r^3$:
$ \rho r^3 = \rho_c r_c^3 + \rho_m (r^3 - r_c^3) $
Rearrange to solve for $\rho_m (r^3 - r_c^3)$:
$ \rho_m (r^3 - r_c^3) = \rho r^3 - \rho_c r_c^3 $
Finally, isolate $\rho_m$:
$ \rho_m = \frac{\rho r^3 - \rho_c r_c^3}{r^3 - r_c^3} $
Divide the numerator and denominator by $r^3$ to match the option format:
$ \rho_m = \frac{\rho - \rho_c \frac{r_c^3}{r^3}}{1 - \frac{r_c^3}{r^3}} = \frac{\rho - \left(\frac{r_c}{r}\right)^3\rho_c}{1-\left(\frac{r_c}{r}\right)^3} $
| Distance from the Sun | Radius of the planet | Incident Solar flux density | Equivalent temperature | |
| Planet A | $d_1$ | $r_1$ | $F_1$ | $T_1$ |
| Planet B | $d_2 = 4d_1$ | $r_2 = 2r_1$ | $F_2$ | $T_2$ |