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Question

A planet of radius $r$ has a core of radius $r_c$ and a mantle. It has no crust. Its mean density is $\rho$ and the density of its core is $\rho_c$. What is the density of the mantle?

The correct answer is
$\frac{\rho - \left(\frac{r_c}{r}\right)^3\rho_c}{1-\left(\frac{r_c}{r}\right)^3}$

Calculating Planet Mantle Density

The mean density ($\rho$) of the planet is the total mass divided by the total volume. The planet consists of a core and a mantle. We need to find the density of the mantle ($\rho_m$).

Planet Composition and Volumes

The planet has a core of radius $r_c$ and a mantle extending to radius $r$. The total volume ($V$) of the planet is the volume of a sphere with radius $r$, and the core volume ($V_c$) is the volume of a sphere with radius $r_c$. The mantle volume ($V_m$) is the difference between the total volume and the core volume.

  • Total Volume: $V = \frac{4}{3}\pi r^3$
  • Core Volume: $V_c = \frac{4}{3}\pi r_c^3$
  • Mantle Volume: $V_m = V - V_c = \frac{4}{3}\pi r^3 - \frac{4}{3}\pi r_c^3 = \frac{4}{3}\pi (r^3 - r_c^3)$

Mass Calculation

The mass of each part is its density multiplied by its volume.

  • Mass of Core: $M_c = \rho_c V_c = \rho_c \left(\frac{4}{3}\pi r_c^3\right)$
  • Mass of Mantle: $M_m = \rho_m V_m = \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)$
  • Total Mass: $M = M_c + M_m = \rho_c \left(\frac{4}{3}\pi r_c^3\right) + \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)$

Deriving Mantle Density

Using the definition of mean density, $\rho = \frac{M}{V}$, we can set up the equation:

$ \rho = \frac{\rho_c \left(\frac{4}{3}\pi r_c^3\right) + \rho_m \left(\frac{4}{3}\pi (r^3 - r_c^3)\right)}{\frac{4}{3}\pi r^3} $

Cancel the common factor $\frac{4}{3}\pi$:

$ \rho = \frac{\rho_c r_c^3 + \rho_m (r^3 - r_c^3)}{r^3} $

Multiply both sides by $r^3$:

$ \rho r^3 = \rho_c r_c^3 + \rho_m (r^3 - r_c^3) $

Rearrange to solve for $\rho_m (r^3 - r_c^3)$:

$ \rho_m (r^3 - r_c^3) = \rho r^3 - \rho_c r_c^3 $

Finally, isolate $\rho_m$:

$ \rho_m = \frac{\rho r^3 - \rho_c r_c^3}{r^3 - r_c^3} $

Divide the numerator and denominator by $r^3$ to match the option format:

$ \rho_m = \frac{\rho - \rho_c \frac{r_c^3}{r^3}}{1 - \frac{r_c^3}{r^3}} = \frac{\rho - \left(\frac{r_c}{r}\right)^3\rho_c}{1-\left(\frac{r_c}{r}\right)^3} $

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Important Questions from Planetary Bodies

  1. The correct sequence of planets in order of increasing surface temperature is:
  2. Atmosphere of planet Mars is almost entirely made up of $\text{CO}_2$. But the surface temperature of Mars is less than that of the Earth because:
  3. Consider two planets A and B with radii $2r$ and $r$, respectively. Let their distances from the Sun be $d$ and $2d$, respectively. The solar constants for A ($F_{\text{SA}}$) and B ($F_{\text{SB}}$) are related by
  4. Consider two planets 'A' and 'B' with the following characteristics. The relationship between $T_1$ and $T_2$ is
    Distance from the SunRadius of the planetIncident Solar flux densityEquivalent temperature
    Planet A$d_1$$r_1$$F_1$$T_1$
    Planet B$d_2 = 4d_1$$r_2 = 2r_1$$F_2$$T_2$
  5. Venus is closer to the Sun than Earth, and therefore solar energy incident on Venus is higher than that on Earth. However, the effective radiating temperature of Venus is lower than that of the Earth, because
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