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Question

Given that \(109^{0.64} = x\), \(109^{0.83} = y\) and \(x^{z} = y^{5}\), then the value of \(z\) is close to:

This question was previously asked in
RRB Group D 2025 Question Paper (9-Aug-2026) (Shift 1)
The correct answer is

6.48

Take logarithms (base 109). From \(109^{0.64} = x\), we have \(\log_{109} x = 0.64\); from \(109^{0.83} = y\), we have \(\log_{109} y = 0.83\).

From \(x^{z} = y^{5}\): \(z \log_{109} x = 5 \log_{109} y\).

Substitute: \(z \times 0.64 = 5 \times 0.83 = 4.15\).

Therefore \(z = \dfrac{4.15}{0.64} \approx 6.48\).

Hence, the value of \(z\) is close to 6.48.

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