Assertion A : Repeated measures ANOVA permits the researcher to determine the significance of mean differences on the same subjects over repeated trials.
Reason R : Repeated measures ANOVA is not used in testing designs where subjects are measured before, during and after the treatment.
In light of the above statements, choose the correct answer from the options given below
Assertion A Analysis
Assertion A states that Repeated Measures ANOVA allows researchers to determine the significance of mean differences for the same subjects across repeated trials or conditions. This is the fundamental purpose of Repeated Measures ANOVA (also known as within-subjects ANOVA). It is designed precisely to analyze data collected from the same participants at multiple time points or under different treatment variations.
Therefore, Assertion A is true.
Reason R Analysis
Reason R claims that Repeated Measures ANOVA is not used in testing designs where subjects are measured before, during, and after a treatment. This statement is incorrect. A common application of Repeated Measures ANOVA is precisely in analyzing data from such pre-test, intra-test, and post-test designs. The measurements taken at these different time points on the same subjects constitute the repeated measures.
Therefore, Reason R is false.
Conclusion
Based on the analysis:
- Assertion A is true.
- Reason R is false.
This aligns with the option stating that Assertion A is true but Reason R is false.
Important Questions from Probability and Statistics
In a frequency curve, what is plotted on the vertical axis?
If the probability of a bad reaction from a certain injection is 0.001, the chance that out of 2000 individuals, more than two will suffer of a bad reaction is
If x and y are deviation from mean x̅ and y̅ respectively and if r = 0.5, ∑xy = 120, σy = 8 and ∑x 2= 90, what is the value of 'n' ?
In an examination involving multiple choice questions, a student works out the solution in 50% of the questions. In the remaining questions the student guesses the answer. However, when the answer is guessed the probability that it is correct is 0.30. When the student works out the solutions it may be wrong with probability 0.10.
If the answer to a particular question is correct, what is the probability that the student guessed the answer?
The lengths of a large stock of titanium rods follow a normal distribution with a mean (μ) of 440 mm and a standard deviation (σ) of 1 mm. What is the percentage of rods whose lengths lie between 438 mm and 441 mm?
