This problem requires calculating the maximum marks of the examination first, and then finding the percentage of marks scored by Girish's friend.
Girish scored 441 marks. This score was 75 marks less than 30% of the maximum marks.
$ \text{30\% of Max Marks} = \text{Girish's Score} + 75 $
$ \text{30\% of Max Marks} = 441 + 75 = 516 \text{ marks} $
$ 0.30 \times M = 516 $
$ M = \frac{516}{0.30} = \frac{5160}{3} = 1720 \text{ marks} $
The maximum marks for the examination are 1720.
Girish's friend scored 688 marks in the same examination.
$ \text{Friend's Percentage} = \left( \frac{\text{Friend's Score}}{\text{Maximum Marks}} \right) \times 100 $
$ \text{Friend's Percentage} = \left( \frac{688}{1720} \right) \times 100 $
$ \frac{688}{1720} = \frac{688 \div 172}{1720 \div 172} = \frac{4}{10} = 0.4 $
(Alternatively, simplify step-by-step: $ \frac{688}{1720} = \frac{344}{860} = \frac{172}{430} = \frac{86}{215} $. Notice $ 86 = 2 \times 43 $ and $ 215 = 5 \times 43 $. So, $ \frac{2 \times 43}{5 \times 43} = \frac{2}{5} = 0.4 $)
$ \text{Friend's Percentage} = 0.4 \times 100 = 40\% $
The percentage of marks scored by Girish's friend is 40%.
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