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Question

From the pairs of operators given below, identify the ones which commute. Here $l$ and $j$ correspond to the orbital angular momentum and the total angular momentum, respectively.

Angular Momentum Operator Commutation Fundamentals

Two operators, say $Â$ and $B̂$, commute if their commutator, defined as $[Â, B̂] = ÂB̂ - B̂Â$, equals zero.

Mathematically, this condition is $[Â, B̂] = 0$.

Analyzing Commuting Operator Pairs

We investigate the provided pairs involving orbital angular momentum (l) and total angular momentum (j).

Operator Pair: l2 and j2

  • Total angular momentum j is defined as j = l + s, where s is spin angular momentum.
  • Squaring this gives j2 = (l + s)2 = l2 + s2 + 2l·s.
  • In standard quantum mechanics treatments, l2 and j2 are typically chosen to commute. This is because they can be simultaneously diagonalized in a common basis, reflecting different aspects of angular momentum magnitude.
  • Therefore, the commutator $[l2, j2] = 0$, indicating this pair commutes.

Operator Pair: j2 and jz

  • The square of an angular momentum operator (j2) inherently commutes with its projection onto any axis (jz).
  • This is a fundamental property of angular momentum algebra in quantum mechanics.
  • Consequently, $[j2, jz] = 0$, confirming this pair commutes.

Operator Pair: j2 and lz

  • Using j2 = l2 + s2 + 2l·s, the commutator is $[j2, lz] = [l2, lz] + [s2, lz] + [2l·s, lz]$.
  • The commutators $[l2, lz]$ and $[s2, lz]$ are both zero, as spin and orbital operators act on independent spaces and have commuting properties with each other's components.
  • However, the term $[l·s, lz]$ is generally non-zero. It can be shown to equal $iħ(lysx - lxsy)$, which is not zero.
  • Thus, $[j2, lz] ≠ 0$, meaning this pair does not commute.

Operator Pair: lz and jz

  • The z-component of total angular momentum is jz = lz + sz.
  • The commutator is $[lz, jz] = [lz, lz + sz] = [lz, lz] + [lz, sz]$.
  • The commutator of an operator with itself is zero: $[lz, lz] = 0$.
  • Components of orbital and spin angular momentum commute: $[lz, sz] = 0$.
  • Therefore, $[lz, jz] = 0 + 0 = 0$, and this pair commutes.

Commuting Operator Identification Summary

The pairs of operators that commute, based on the analysis, are:

  • l2, j2
  • j2, jz
  • lz, jz
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Important Questions from Operators Commutators Heisenberg Picture

  1. The wavefunction of a particle in one dimension is given by 
    $\psi(x) = \begin{cases} M, & -a < x < a \\ 0, & \text{otherwise.} \end{cases}$ 
    Here $M$ and $a$ are positive constants. If $\phi(p)$ is the corresponding momentum space wavefunction, which one of the following plots best represents $|\phi(p)|^2$ ?

  2. An electromagnetic pulse has a pulse width of $10^{-3}$ s. The uncertainty in the momentum of the corresponding photon is of the order of $10^{-N}$ kg m $s^{-1}$, where $N$ is an integer. The value of $N$ is ________ (speed of light = $3 \times 10^8$ m $s^{-1}$, h = $6.6 \times 10^{-34}$ J s)
  3. In cylindrical coordinates $(s, \varphi, z)$, which of the following is a Hermitian operator?
  4. Let $|m\rangle$ and $|n\rangle$ denote the energy eigenstates of a one-dimensional simple harmonic oscillator. The position and momentum operators are $\hat{X}$ and $\hat{P}$, respectively. The matrix element $\langle m|\hat{P}\hat{X}|n\rangle$ is non-zero when
  5. Let $|\psi_1\rangle = \begin{pmatrix} 1 \\ 0 \end{pmatrix}$, $|\psi_2\rangle = \begin{pmatrix} 0 \\ 1 \end{pmatrix}$ represent two possible states of a two-level quantum system. The state obtained by the incoherent superposition of $|\psi_1\rangle$ and $|\psi_2\rangle$ is given by a density matrix that is defined as $\rho ≡  c_1|\psi_1\rangle\langle\psi_1| + c_2|\psi_2\rangle\langle\psi_2|$. If $c_1 = 0.4$ and $c_2 = 0.6$, the matrix element $\rho_{22}$ (rounded off to one decimal place) is ________

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