Fourth proportion to 12, 18 and 6 is same as the third proportion to k and 6. What is the value of k?
4
This problem requires us to understand the concepts of fourth proportion and third proportion and then use the given condition to find the value of 'k'.
When four numbers a, b, c, and d are in proportion, it means that the ratio of the first two is equal to the ratio of the last two. This is written as a : b :: c : d, which is equivalent to $\frac{a}{b} = \frac{c}{d}$. In this case, 'd' is called the fourth proportion.
We are given the numbers 12, 18, and 6, and we need to find the fourth proportion. Let the fourth proportion be 'x'. So, we have the proportion:
$12 : 18 :: 6 : x$
Writing this as an equation:
$\frac{12}{18} = \frac{6}{x}$
To solve for x, we can cross-multiply:
$12 \times x = 18 \times 6$
$12x = 108$
Now, divide by 12 to find x:
$x = \frac{108}{12}$
$x = 9$
So, the fourth proportion to 12, 18, and 6 is 9.
When three numbers a, b, and c are in proportion, and 'b' is the mean proportion, it means that a : b :: b : c, which is equivalent to $\frac{a}{b} = \frac{b}{c}$. In this case, 'c' is called the third proportion to a and b.
We are given the numbers k and 6, and 6 is the mean proportion. We need to find the third proportion. Let the third proportion be 'y'. So, we have the proportion:
$k : 6 :: 6 : y$
Writing this as an equation:
$\frac{k}{6} = \frac{6}{y}$
The problem states that the fourth proportion (which we found to be 9) is the same as the third proportion to k and 6. This means the value of 'y' from the second step is 9.
So, we substitute y = 9 into the equation for the third proportion:
$\frac{k}{6} = \frac{6}{9}$
Now, we need to solve this equation for k. First, we can simplify the fraction on the right side:
$\frac{6}{9} = \frac{2 \times 3}{3 \times 3} = \frac{2}{3}$
So the equation becomes:
$\frac{k}{6} = \frac{2}{3}$
To find k, multiply both sides by 6:
$k = \frac{2}{3} \times 6$
$k = \frac{12}{3}$
$k = 4$
The value of k is 4.
The fourth proportion to 12, 18, and 6 is 9. The third proportion to k and 6 is also 9. By setting up the equation $\frac{k}{6} = \frac{6}{9}$ and solving for k, we find that $k=4$.
| Concept | Definition | Formula |
|---|---|---|
| Proportion | Equality of two ratios | a : b = c : d or $\frac{a}{b} = \frac{c}{d}$ |
| Fourth Proportion | In a : b = c : d, d is the fourth proportion to a, b, and c. | $d = \frac{b \times c}{a}$ |
| Third Proportion | In a : b = b : c, c is the third proportion to a and b. (b is the mean proportion) | $c = \frac{b^2}{a}$ |
| Term | Description | Example |
|---|---|---|
| Ratio | Comparison of two quantities by division. | 3:4 or $\frac{3}{4}$ |
| Proportion | Statement that two ratios are equal. | $\frac{2}{3} = \frac{4}{6}$ |
| Terms of Proportion | In a : b :: c : d, a, b, c, d are terms. 'a' and 'd' are extremes, 'b' and 'c' are means. Product of extremes = Product of means (ad = bc). | In 2:3 :: 4:6, 2 and 6 are extremes, 3 and 4 are means. $2 \times 6 = 12$, $3 \times 4 = 12$. |
| Mean Proportion | If a : b :: b : c, b is the mean proportion between a and c. $b^2 = ac$. | Mean proportion between 4 and 9 is $\sqrt{4 \times 9} = \sqrt{36} = 6$. (4:6::6:9) |
Beyond basic proportions, there are different types based on how quantities relate:
Understanding these relationships helps in solving various problems involving ratios and proportions.
If p is the third proportional to 8, 20 and q is the fourth proportional to 3, 5, 24, then find the value of (2p + q).
Find the ratio between the fourth proportional of 12, 16, 6 and the third proportional of 4, 6.
The fourth proportion to 12, 18, 6 is equal to the third proportion to 4, k. What is the value of k?
What is the ratio of the fourth proportional of 2, 5, 6 and the fourth proportional of 6, 8, 9?
The fourth proportion to 12, 24 and 27 is the same as the third proportion to A and 36. What is the value of A?