Find the ratio between the fourth proportional of 12, 16, 6 and the third proportional of 4, 6.
8 ∶ 9
This problem requires us to find the ratio between two values derived from proportions: the fourth proportional of three given numbers and the third proportional of two given numbers. Let's break down how to find each of these values.
When four numbers, say \(a, b, c,\) and \(d\), are in proportion, they satisfy the relationship \(a:b :: c:d\). This can be written as the equality of two ratios: \(\frac{a}{b} = \frac{c}{d}\). Here, \(d\) is called the fourth proportional to \(a, b,\) and \(c\).
We are given the numbers 12, 16, and 6, and we need to find the fourth proportional. Let the fourth proportional be \(x\). So, we have the proportion:
\(12 : 16 :: 6 : x\)
Writing this as fractions, we get:
\(\frac{12}{16} = \frac{6}{x}\)
To solve for \(x\), we can cross-multiply:
\(12 \times x = 16 \times 6\)
\(12x = 96\)
Now, divide both sides by 12:
\(x = \frac{96}{12}\)
\(x = 8\)
So, the fourth proportional of 12, 16, and 6 is 8.
When three numbers, say \(a, b,\) and \(c\), are in continued proportion, they satisfy the relationship \(a:b :: b:c\). This means the ratio of the first two terms is equal to the ratio of the second and third terms. This can be written as the equality of two ratios: \(\frac{a}{b} = \frac{b}{c}\). Here, \(c\) is called the third proportional to \(a\) and \(b\), and \(b\) is called the mean proportional between \(a\) and \(c\).
We are given the numbers 4 and 6, and we need to find the third proportional. Let the third proportional be \(y\). The continued proportion is:
\(4 : 6 :: 6 : y\)
Writing this as fractions, we get:
\(\frac{4}{6} = \frac{6}{y}\)
To solve for \(y\), we can cross-multiply:
\(4 \times y = 6 \times 6\)
\(4y = 36\)
Now, divide both sides by 4:
\(y = \frac{36}{4}\)
\(y = 9\)
So, the third proportional of 4 and 6 is 9.
The question asks for the ratio between the fourth proportional of 12, 16, 6 and the third proportional of 4, 6.
The ratio is simply the first value compared to the second value:
Ratio = (Fourth proportional) : (Third proportional)
Ratio = 8 : 9
This ratio cannot be simplified further, as 8 and 9 have no common factors other than 1.
Here is a summary of the calculated values:
| Concept | Given Numbers | Calculation | Result |
|---|---|---|---|
| Fourth Proportional | 12, 16, 6 | \(\frac{12}{16} = \frac{6}{x} \implies 12x = 96 \implies x = 8\) | 8 |
| Third Proportional | 4, 6 | \(\frac{4}{6} = \frac{6}{y} \implies 4y = 36 \implies y = 9\) | 9 |
The ratio of these results is 8 : 9.
Understanding different types of proportionals is crucial:
| Term | Definition | Relationship |
|---|---|---|
| Ratio | A comparison of two quantities. | \(a:b\) or \(\frac{a}{b}\) |
| Proportion | An equality of two ratios. | \(\frac{a}{b} = \frac{c}{d}\) |
| Fourth Proportional | In \(a:b = c:d\), \(d\) is the fourth proportional. | \(ad = bc\) |
| Third Proportional | In \(a:b = b:c\), \(c\) is the third proportional. | \(ac = b^2\) |
| Mean Proportional | In \(a:b = b:c\), \(b\) is the mean proportional between \(a\) and \(c\). | \(b^2 = ac\) |
Ratios and proportions are fundamental concepts in arithmetic and algebra. They are used to compare quantities and understand relationships between them.
If p is the third proportional to 8, 20 and q is the fourth proportional to 3, 5, 24, then find the value of (2p + q).
The fourth proportion to 12, 18, 6 is equal to the third proportion to 4, k. What is the value of k?
What is the ratio of the fourth proportional of 2, 5, 6 and the fourth proportional of 6, 8, 9?
The fourth proportion to 12, 24 and 27 is the same as the third proportion to A and 36. What is the value of A?
Fourth proportion to 12, 18 and 6 is same as the third proportion to k and 6. What is the value of k?