College Admission Logic Puzzle Solution
Given Information Summary
- Four students: Amit, Bharat, Chandan, Danish.
- Four colleges: BDS, IIMT, DPS, IMS.
- Four courses: BA, BBM, BSc, BCom.
- Chandan: IMS, BA.
- Amit: BDS, BBM.
- Danish: Opted for BSc.
- Constraint: Student in IIMT did not opt for BSc.
Step-by-Step Deduction
We need to determine which student was admitted to DPS.
- Known Assignments:
- Chandan is in IMS and pursuing BA.
- Amit is in BDS and pursuing BBM.
- Danish's Course: Danish opted for BSc.
- Applying the Constraint: The student admitted to IIMT did not choose BSc. Since Danish chose BSc, Danish cannot be the student admitted to IIMT.
- Available Colleges: The colleges remaining are DPS and IIMT. The students remaining are Bharat and Danish.
- Placing Danish: Because Danish cannot be in IIMT (due to the BSc constraint), Danish must be admitted to DPS.
- Placing Bharat: By elimination, Bharat must be the student admitted to IIMT.
- Remaining Course: The only course left is BCom. Bharat must have opted for BCom.
The final arrangement is:
| Student | College | Course |
|---|---|---|
| Amit | BDS | BBM |
| Bharat | IIMT | BCom |
| Chandan | IMS | BA |
| Danish | DPS | BSc |
Therefore, Danish took admission in DPS.
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Important Questions from Logical Puzzle
Which two numbers should be interchanged to make the given equation correct?
9 + 7 × 5 – 18 ÷ 2 = 3 × 4 – 10 + 45 ÷ 5Select the correct combination of mathematical signs that can sequentially replace the * signs and balance the equation.
60 * 2 * 3 * 6 * 5 * 43
Which of the following interchange of numbers and mathematical signs would make the given equation correct?
30 ÷ 6 × 4 + 15 - 35 = 25
Which two signs need to be interchanged to make the following equation correct?
23 + 84 ÷ 14 × 8 − 3 = 5
Select the correct combination of mathematical signs that can sequentially replace the * signs and make the equation correct.
68 * 138* 23 * 54 * 20
