Four dice are rolled. What is the probability of getting a total of the numbers on the dice as 7?
5/324
The number of ways four dice can show a total of 7 equals the number of integer solutions of \(a+b+c+d=7\) with \(1\le a,b,c,d\le6\), which works out to \(\binom{6}{3}=20\). The total number of outcomes is \(6^{4}=1296\), so the required probability is \(\frac{20}{1296}=\frac{5}{324}\).
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