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Question

In a population of 210 individuals, 72 are smokers and 138 are non - smokers. If a person is selected with an equal chance to each category, what is the probability of that person being a smoker ?

The correct answer is
0.34

Probability Calculation for Smoker Selection

To find the probability of selecting a smoker, we use the basic probability formula:

$ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} $

Applying the Formula

  • Total population: 210 individuals
  • Number of smokers (favorable outcomes): 72
  • Probability of selecting a smoker:

$ P(\text{Smoker}) = \frac{72}{210} $

Result Calculation

Now, we simplify the fraction:

$ P(\text{Smoker}) = \frac{72 \div 6}{210 \div 6} = \frac{12}{35} $

Converting the fraction to a decimal:

$ \frac{12}{35} \approx 0.342857... $

Rounding to two decimal places, the probability is approximately 0.34.

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Important Questions from Probability of Random Experiments

  1. A, B, C and D are mutually exclusive and exhaustive events.

    If 2P(A) = 3P(B) = 4P(C) = 5P(D), then what is 77P(A) equal to ?

  2. A fair coin is tossed 6 times. What is the probability of getting a result in the 6t h toss which is different from those obtained in the first five tosses ?

  3. Two cards are drawn successively without replacement from a well-shuffled pack of 52 cards. The probability of drawing two aces is

  4. A biased coin with the probability of getting head equal to \(\frac{1}{4}\) is tossed five times. What is the probability of getting tail in all the first four tosses followed by head ? 

  5. Three dice are thrown. What is the probability that each face shows only multiples of 3 ?

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