To find the probability of selecting a smoker, we use the basic probability formula:
$ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} $
$ P(\text{Smoker}) = \frac{72}{210} $
Now, we simplify the fraction:
$ P(\text{Smoker}) = \frac{72 \div 6}{210 \div 6} = \frac{12}{35} $
Converting the fraction to a decimal:
$ \frac{12}{35} \approx 0.342857... $
Rounding to two decimal places, the probability is approximately 0.34.
A, B, C and D are mutually exclusive and exhaustive events.
If 2P(A) = 3P(B) = 4P(C) = 5P(D), then what is 77P(A) equal to ?
A fair coin is tossed 6 times. What is the probability of getting a result in the 6t h toss which is different from those obtained in the first five tosses ?
Two cards are drawn successively without replacement from a well-shuffled pack of 52 cards. The probability of drawing two aces is
A biased coin with the probability of getting head equal to \(\frac{1}{4}\) is tossed five times. What is the probability of getting tail in all the first four tosses followed by head ?
Three dice are thrown. What is the probability that each face shows only multiples of 3 ?