The following table shows the Income and Expenditure (in million Rs.) of five companies A-E in the year 2021. The percent profit or loss of a company is given by: (Profit/Loss) % = [(Income - Expenditure)/ Expenditure] × 100 Based on the data in the table, answer the questions. Company wise Income and Expenditure in the year 2021Company Income (in million Rs.) Expenditure (in million Rs.) A 35 45 B 50 40 C 40 45 D 40 30 E 50 45
For Company E, if the expenditure had increased by 20% in the year 2021 from the year 2020 and the company had earned a profit of 10% in 2020, then the company's income (in million Rs.) in 2020 was ________.
41.25
The question provides a table showing the Income and Expenditure for five different companies (A, B, C, D, and E) in the year 2021. It also gives the formula to calculate the profit or loss percentage:
\( \text{(Profit/Loss) \%} = \left[ \frac{\text{Income} - \text{Expenditure}}{\text{Expenditure}} \right] \times 100 \)
We need to focus on Company E and determine its income in the year 2020, given specific information about its expenditure change from 2020 to 2021 and its profit percentage in 2020.
Let's extract the relevant data for Company E from the provided table:
| Company | Income (in million Rs.) | Expenditure (in million Rs.) |
|---|---|---|
| E | 50 | 45 |
So, for Company E in 2021:
The question states that Company E's expenditure in 2021 had increased by 20% from the year 2020.
Let \(E_{2020}\) be the expenditure of Company E in 2020.
The expenditure in 2021 is \(E_{2020}\) plus a 20% increase on \(E_{2020}\).
This can be written as:
\( E_{2021} = E_{2020} + 20\% \text{ of } E_{2020} \)
\( E_{2021} = E_{2020} + \frac{20}{100} \times E_{2020} \)
\( E_{2021} = E_{2020} \times \left( 1 + \frac{20}{100} \right) \)
\( E_{2021} = E_{2020} \times (1 + 0.20) \)
\( E_{2021} = 1.20 \times E_{2020} \)
We know \(E_{2021} = 45\) million Rs. Substitute this value into the equation:
\( 45 = 1.20 \times E_{2020} \)
Now, solve for \(E_{2020}\):
\( E_{2020} = \frac{45}{1.20} \)
\( E_{2020} = \frac{45}{\frac{120}{100}} = \frac{45 \times 100}{120} = \frac{4500}{120} \)
\( E_{2020} = \frac{450}{12} = \frac{150}{4} = 37.5 \)
So, Company E's expenditure in 2020 was 37.5 million Rs.
The question states that Company E had a profit of 10% in the year 2020.
Let \(I_{2020}\) be the income of Company E in 2020.
Using the profit percentage formula for 2020:
\( \text{Profit \% in 2020} = \left[ \frac{I_{2020} - E_{2020}}{E_{2020}} \right] \times 100 \)
We are given that Profit % in 2020 is 10%, and we calculated \(E_{2020} = 37.5\).
\( 10 = \left[ \frac{I_{2020} - 37.5}{37.5} \right] \times 100 \)
Divide both sides by 100:
\( \frac{10}{100} = \frac{I_{2020} - 37.5}{37.5} \)
\( 0.10 = \frac{I_{2020} - 37.5}{37.5} \)
Multiply both sides by 37.5:
\( 0.10 \times 37.5 = I_{2020} - 37.5 \)
\( 3.75 = I_{2020} - 37.5 \)
Now, solve for \(I_{2020}\) by adding 37.5 to both sides:
\( I_{2020} = 3.75 + 37.5 \)
\( I_{2020} = 41.25 \)
So, Company E's income in 2020 was 41.25 million Rs.
The company's income in 2020 was 41.25 million Rs.
| Year | Expenditure Calculation | Expenditure (million Rs.) | Profit % | Income Calculation | Income (million Rs.) |
|---|---|---|---|---|---|
| 2021 | Given | 45 | \( \frac{50-45}{45} \times 100 \approx 11.11\% \) | Given | 50 |
| 2020 | \( 45 / 1.20 \) | 37.5 | 10% (Given) | \( 37.5 + 10\% \text{ of } 37.5 = 1.10 \times 37.5 \) | 41.25 |
Understanding profit, loss, income, and expenditure is fundamental in business and data analysis. Here's a quick recap:
The given formula \( \left[ \frac{\text{Income} - \text{Expenditure}}{\text{Expenditure}} \right] \times 100 \) correctly represents both profit and loss percentage. If Income > Expenditure, the numerator is positive (profit). If Income < Expenditure, the numerator is negative (loss).
When dealing with percentage changes year-on-year, remember that the percentage change is usually calculated with respect to the previous year's value. If something increases by X%, the new value is the original value multiplied by \((1 + X/100)\). If it decreases by X%, the new value is the original value multiplied by \((1 - X/100)\).
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?