Tables I and II below present analysis of people involved in a total of 10,000 road accidents which happened in Delhi during the year 2020 in accordance to both analysis of severity and fatalities. Taking it. on an average three (3) people were involved in each road accident. In accordance with the data in the tables. answer the questions: Table - I: Analysis of Severity Uninjured 47% First-Aid Required 6% Mild Bruises 9% Hospitalization 19% Fatalities 19% Table - II: Analysis of Fatalities Head Injuries 69% Damage to Internal Organs 21% Fire Casuality 3% Blood-Loss 7%
For a person involved in an accident, the likelihood of escaping uninjured is P times that of dying by Fire. Then, approximately P will be equal to ________.
82
The question asks us to determine the ratio of the likelihood of a person escaping uninjured in a road accident to the likelihood of dying by Fire. We are provided with data from two tables analysing 10,000 road accidents involving an average of 3 people per accident in Delhi during 2020.
First, let's understand the total number of people involved in these accidents:
Table I provides the analysis of severity for these people:
| Severity | Percentage |
|---|---|
| Uninjured | 47% |
| First-Aid Required | 6% |
| Mild Bruises | 9% |
| Hospitalization | 19% |
| Fatalities | 19% |
Table II provides an analysis of the causes of fatalities. Note that these percentages are out of the total fatalities, not out of the total people involved.
| Cause of Fatality | Percentage (of Fatalities) |
|---|---|
| Head Injuries | 69% |
| Damage to Internal Organs | 21% |
| Fire Casuality | 3% |
| Blood-Loss | 7% |
From Table I, the percentage of people who escaped uninjured is 47%. This percentage is based on the total number of people involved (30,000).
The likelihood (or probability) of a randomly selected person involved in an accident escaping uninjured is the percentage of uninjured people divided by 100.
Likelihood of escaping uninjured = \(\frac{\text{Percentage Uninjured}}{100} = \frac{47}{100} = 0.47\)
To find the likelihood of dying by Fire, we need to combine information from both tables.
From Table I, the percentage of people who suffered fatalities is 19% of the total people involved.
From Table II, the percentage of fatalities caused by Fire is 3% of the total fatalities.
So, the percentage of total people involved who died by Fire is 3% of the 19% fatalities.
Percentage of people dying by Fire = (Percentage of Fatalities) \(\times\) (Percentage of Fire Casualty out of Fatalities)
Percentage of people dying by Fire = \(19\% \times 3\% = \frac{19}{100} \times \frac{3}{100}\)
Percentage of people dying by Fire = \(0.19 \times 0.03 = 0.0057\)
The likelihood (or probability) of a randomly selected person involved in an accident dying by Fire is this percentage divided by 100.
Likelihood of dying by Fire = \(\frac{0.0057}{1} = 0.0057\)
The question states that the likelihood of escaping uninjured is P times that of dying by Fire.
Likelihood of escaping uninjured = P \(\times\) Likelihood of dying by Fire
Rearranging the formula to find P:
\(P = \frac{\text{Likelihood of escaping uninjured}}{\text{Likelihood of dying by Fire}}\)
Substitute the calculated likelihood values:
\(P = \frac{0.47}{0.0057}\)
Now, let's calculate the value of P:
\(P \approx 82.456\)
The question asks for the approximate value of P.
Comparing this value to the given options:
The value 82.456 is closest to 82.
Thus, approximately P will be equal to 82.
| Event | Calculation | Likelihood (Probability) |
|---|---|---|
| Escaping Uninjured | 47% of total people | 0.47 |
| Dying by Fire | 3% of 19% of total people | \(0.19 \times 0.03 = 0.0057\) |
| Ratio P | \(\frac{\text{Likelihood Uninjured}}{\text{Likelihood Dying by Fire}}\) | \(\frac{0.47}{0.0057} \approx 82.456\) |
In this problem, we used concepts of probability based on percentages derived from statistical data. Here's a brief explanation:
Understanding how to work with percentages and conditional probabilities is crucial for interpreting data presented in tables like these, especially in accident analysis and risk assessment.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?