For a particle in uniform circular motion (radius R and angular velocity ω), the magnitude and direction of acceleration, respectively are
ω2R, towards the centre of the circle
In uniform circular motion, the speed stays constant but the direction of velocity continuously changes, which requires a centripetal (centre-seeking) acceleration.
Using \(v = \omega R\), the centripetal acceleration is \(a = \dfrac{v^2}{R} = \dfrac{(\omega R)^2}{R} = \omega^2 R\), and it is always directed radially inward, towards the centre of the circle, so that the particle keeps curving along the circular path instead of moving off in a straight line.
Hence, the magnitude and direction of the acceleration are ω2R, towards the centre of the circle.
Velocity (m/s)-time (s) graph is plotted for the motion of two cars A and B for 10 s, when the cars are initially at rest and acquire final velocities as VA and VB, respectively. The respective straight lines of the graph make angles 30° and 60°, respectively with the x-axis (time). The difference in velocities VB and VA is
An object is covering distance in direct proportion to the square of time elapsed. What conclusion can be drawn about the motion of the object?
If the distance time graph of the motion of an object is a straight line but not parallel to the time axis, then it may be concluded that the object is moving with a:
Which of the following changes when a body performs uniform circular motion?
Vehicles have treaded tires so that it_______.
The distance time graph for an object, moving with a constant speed will be a