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Question

For a particle in uniform circular motion (radius R and angular velocity ω), the magnitude and direction of acceleration, respectively are

This question was previously asked in
UPSC CAPF 2026 General Ability and Intelligence Question Paper (19-Jul-2026)
The correct answer is

ω2R, towards the centre of the circle

In uniform circular motion, the speed stays constant but the direction of velocity continuously changes, which requires a centripetal (centre-seeking) acceleration.

Using \(v = \omega R\), the centripetal acceleration is \(a = \dfrac{v^2}{R} = \dfrac{(\omega R)^2}{R} = \omega^2 R\), and it is always directed radially inward, towards the centre of the circle, so that the particle keeps curving along the circular path instead of moving off in a straight line.

Hence, the magnitude and direction of the acceleration are ω2R, towards the centre of the circle.

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