For a causal discrete-time LTI system with transfer function
$H(z) = \frac{2z^2+3}{(z+\frac{1}{3})(z-\frac{1}{3})}$,
which of the following statements is/are true?
Given the transfer function for a causal discrete-time LTI system: $H(z) = \frac{2z^2+3}{(z+\frac{1}{3})(z-\frac{1}{3})} = \frac{2z^2+3}{z^2 - \frac{1}{9}}$
A causal discrete-time LTI system is BIBO stable if all its poles lie strictly inside the unit circle ($|z| < 1$).
Since both poles are inside the unit circle, the system is stable.
A causal system is minimum phase if all its poles and zeros lie strictly inside the unit circle.
Since there are zeros outside the unit circle, the system is not minimum phase.
For a causal system, the initial value of the impulse response, $h[0]$, is found by evaluating $H(z)$ as $z \to \infty$.
The initial value of the impulse response, $h[0]$, is 2.
The final value, $h[\infty]$, is determined using the final value theorem. This theorem applies if all poles of $z H(z)$ lie strictly inside the unit circle.
Therefore, the final value of the impulse response, $h[\infty]$, is 0.
Based on the analysis:
The correct statements are 1, 3, and 4.
The z transform of e −t sampled at 10 Hz will be:
What is the set of all values of z for which X(z) attains a finite value?
The z transform of the following real exponential sequence
x(n) = {a n ;n >= 0} , {= 0 ; n < 0} and a > 0 is given by
What will be the z-transform of a Unit step function ?
The z-transform of a causal periodic signal can be determined from the knowledge of the z-transform of its: