Identifying the Alphabetical Pattern

The question presents a letter analogy based on the English alphabet's order. We need to find the relationship between the letter groups and apply it.

Let's analyze the first pair: FKEP is related to EIBL.

We represent the letters by their position in the alphabet:

• F = 6, K = 11, E = 5, P = 16
• E = 5, I = 9, B = 2, L = 12

Calculating the difference between the positions:

• 1st letter: F(6) to E(5) = $6 - 1 = 5$
• 2nd letter: K(11) to I(9) = $11 - 2 = 9$
• 3rd letter: E(5) to B(2) = $5 - 3 = 2$
• 4th letter: P(16) to L(12) = $16 - 4 = 12$

The pattern is to subtract 1 from the first letter's position, 2 from the second, 3 from the third, and 4 from the fourth.

Verifying the Pattern

Let's check this pattern with the second pair: JMHT is related to IKEP.

• J = 10, M = 13, H = 8, T = 20
• I = 9, K = 11, E = 5, P = 16

Applying the pattern (-1, -2, -3, -4):

• 1st letter: J(10) - 1 = 9 (I)
• 2nd letter: M(13) - 2 = 11 (K)
• 3rd letter: H(8) - 3 = 5 (E)
• 4th letter: T(20) - 4 = 16 (P)

The pattern holds true for the second pair.

Applying the Pattern to PQNW

Now, we apply the same logic (-1, -2, -3, -4) to PQNW.

• P = 16, Q = 17, N = 14, W = 23

Calculate the new letter positions:

• 1st letter: P(16) - 1 = 15 → O
• 2nd letter: Q(17) - 2 = 15 → O
• 3rd letter: N(14) - 3 = 11 → K
• 4th letter: W(23) - 4 = 19 → S

Combining the resulting letters, we get OOKS.

Conclusion

Following the established pattern, PQNW is related to OOKS.