Five students A, B, C, D and E attend five different schools S1, S2, S3, S4 and S5 (not necessarily in the same order). Each also likes a different subject namely D1, D2, D3, D4 and D5 (not necessarily in the same order). A goes to S5 but does not like D3. C likes D4. The one who goes to S1 likes D5. D goes to S3. E does not like D5. The one who goes to S2 likes D1.
Which of the following statement is correct?
I. B likes D5.
II. C goes to S4.

Question

Five students A, B, C, D and E attend five different schools S1, S2, S3, S4 and S5 (not necessarily in the same order). Each also likes a different subject namely D1, D2, D3, D4 and D5 (not necessarily in the same order). A goes to S5 but does not like D3. C likes D4. The one who goes to S1 likes D5. D goes to S3. E does not like D5. The one who goes to S2 likes D1.

Which of the following statement is correct?

I. B likes D5.

II. C goes to S4.

Prepp Team · Accepted Answer

Solving the Student, School, and Subject Logic Puzzle

This problem requires us to deduce the relationships between five students (A, B, C, D, E), five schools (S1, S2, S3, S4, S5), and five subjects (D1, D2, D3, D4, D5) based on the given clues. We can use a process of elimination and deduction, often aided by a table, to solve this type of logic puzzle.

Analyzing the Given Clues

Let's list out the facts provided:

Student A goes to School S5.
Student A does not like Subject D3.
Student C likes Subject D4.
The student who goes to School S1 likes Subject D5.
Student D goes to School S3.
Student E does not like Subject D5.
The student who goes to School S2 likes Subject D1.

Building a Deduction Table

We can use a table to keep track of the information and deductions.

Student	School	Subject
A	S5	Not D3
B	?	?
C	?	D4
D	S3	?
E	?	Not D5

Step-by-Step Deduction

Let's use the clues to fill in the gaps:

We know A goes to S5, C likes D4, and D goes to S3.
"The one who goes to S1 likes D5." Look at the students who could go to S1 and like D5.
- A goes to S5, so A is not at S1.
- C likes D4, so C does not like D5.
- D goes to S3, so D is not at S1.
- E does not like D5.
- This leaves only B. Therefore, B goes to S1 and B likes D5.
Now we have:
- A: S5, Not D3
- B: S1, D5
- C: ?, D4
- D: S3, ?
- E: ?, Not D5
Schools remaining: S2, S4. Students remaining for these schools: C, E. Subjects remaining: D1, D2, D3.
"The one who goes to S2 likes D1." Who could go to S2? C or E.
- If C goes to S2, C would like D1. But we know C likes D4. This is a contradiction.
- Therefore, E goes to S2 and E likes D1.
Now we have:
- A: S5, Not D3
- B: S1, D5
- C: ?, D4
- D: S3, ?
- E: S2, D1
Schools remaining: S4 (for C). Subject remaining for C: C goes to S4.
Remaining students for subjects are A and D. Remaining subjects are D2 and D3.
- A is at S5 and does not like D3. The only remaining subject A can like is D2. So, A likes D2.
- This leaves D to like the remaining subject, D3. So, D likes D3.

Final Relationships

Putting it all together, we get the complete set of relationships:

Student	School	Subject
A	S5	D2
B	S1	D5
C	S4	D4
D	S3	D3
E	S2	D1

Evaluating the Statements

Now let's look at the given statements:

Statement I: B likes D5.
From our deductions, we found that B likes D5. So, Statement I is correct.
Statement II: C goes to S4.
From our deductions, we found that C goes to S4. So, Statement II is correct.

Conclusion

Both Statement I and Statement II are correct based on the given information and logical deduction.

Prepp Team · Answer

Only ।

Prepp Team · Answer

Neither I nor II

Prepp Team · Answer

Only II