We need to find the number of ways to seat five persons (P, Q, R, S, T) in a row based on specific constraints:
Let the positions be numbered 1, 2, 3, 4, 5 from left to right.
Arrangement: $_ R _ _ _$
We have two main possibilities for the positions of P and T in seats {3, 4}.
Arrangement: $_ R P T _$
Arrangement: $_ R T P _$
Summing the valid arrangements from both cases:
Total arrangements = (Arrangements from Case A) + (Arrangements from Case B)
Total arrangements = 2 + 1 = 3
The possible distinct seating arrangements are: $S R P T Q$, $Q R P T S$, and $S R T P Q$.
Six persons P, Q, R, S, T and U are sitting around a circular table facing the center not necessarily in the same order. Consider the following statements:
• P sits next to S and T.
• Q sits diametrically opposite to P.
• The shortest distance between S and R is equal to the shortest distance between T and U.
Based on the above statements, Q is a neighbor of
Seven cars P, Q, R, S, T, U and V are parked in a row not necessarily in that order. The cars T and U should be parked next to each other. The cars S and V also should be parked next to each other, whereas P and Q cannot be parked next to each other. Q and S must be parked next to each other. R is parked to the immediate right of V. T is parked to the left of U.
Based on the above statements, the only INCORRECT option given below is: