83853
This problem requires calculating the volume of a cylinder using its given radius and height.
Given Data:
The formula for the volume ($V$) of a cylinder is:
$V = \pi r^2 h$
First, convert the radius from decimal to a fraction:
$r = 38.5 = \frac{385}{10} = \frac{77}{2}$ cm
Substitute the values into the volume formula:
$V = \frac{22}{7} \times \left(\frac{77}{2}\right)^2 \times 18$
$V = \frac{22}{7} \times \frac{77}{2} \times \frac{77}{2} \times 18$
$V = \frac{22 \times 77 \times 77 \times 18}{7 \times 2 \times 2}$
$V = \frac{22 \times (7 \times 11) \times 77 \times 18}{7 \times 4}$
$V = \frac{22 \times 11 \times 77 \times 18}{4}$
$V = \frac{11 \times 11 \times 77 \times 18}{2}$
$V = 11 \times 11 \times 77 \times 9$
$V = 121 \times 77 \times 9$
$V = 9317 \times 9$
$V = 83853$
The volume of the cylinder is $83853$ $cm^3$.
If a cubical container of length, breadth and height each of 10 cm can contain exactly 1 litre of water, then a spherical container of radius 10.5 cm can contain