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Question

Find the volume of the cylinder whose radius is 21 cm and height is 13 cm. (In $cm^3$ and use $\pi = 22/7$)

The correct answer is
18018

Cylinder Volume Calculation

To find the volume of a cylinder, we use the formula:

$ V = \pi r^2 h $

Where:

  • \( V \) is the volume
  • \( \pi \) is Pi
  • \( r \) is the radius
  • \( h \) is the height

Given Values

  • Radius (\( r \)): 21 cm
  • Height (\( h \)): 13 cm
  • Pi (\( \pi \)): \( \frac{22}{7} \)

Step-by-Step Calculation

  1. Substitute the given values into the volume formula:

    $ V = \frac{22}{7} \times (21 \text{ cm})^2 \times 13 \text{ cm} $

  2. Calculate the square of the radius:

    $ (21 \text{ cm})^2 = 21 \text{ cm} \times 21 \text{ cm} = 441 \text{ cm}^2 $

  3. Substitute the squared radius back into the formula:

    $ V = \frac{22}{7} \times 441 \text{ cm}^2 \times 13 \text{ cm} $

  4. Simplify the calculation by dividing 441 by 7:

    $ \frac{441}{7} = 63 $

    $ V = 22 \times 63 \text{ cm}^2 \times 13 \text{ cm} $

  5. Multiply the remaining numbers:

    $ V = 1386 \text{ cm}^2 \times 13 \text{ cm} $

    $ V = 18018 \text{ cm}^3 $

Final Volume

The volume of the cylinder is 18018 $cm^3$.

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Important Questions from Solid Figures

  1. Find the volume of the cylinder whose radius is 38.5 cm and height is 18 cm. (use $\pi = 22/7$ and In $cm^3$)
  2. Find the surface area of the sphere (in $cm^2$) whose radius is 168 cm and $\pi = 22/7$.
  3. A solid spherical ball made of iron is melted and two new balls are made whose diameters are in the ratio of 1:2. The ratio of the volume of the smaller new ball to the original ball is
  4. If a cubical container of length, breadth and height each of 10 cm can contain exactly 1 litre of water, then a spherical container of radius 10.5 cm can contain

  5. Eight metallic balls of one centimetre radius each are melted into one ball. The diameter of the new ball is
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