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Question

Find the value of \( \sqrt{125 + \sqrt{344 + \sqrt{289}}} \).

The correct answer is
12

Solving Nested Square Roots Step-by-Step

To find the value of the expression \( \sqrt{125 + \sqrt{344 + \sqrt{289}}} \), we need to simplify it by starting from the innermost square root and working outwards.

Step 1: Simplify the Innermost Square Root

First, calculate the square root of 289:

  • \( \sqrt{289} \)
  • We know that \( 17 \times 17 = 289 \).
  • Therefore, \( \sqrt{289} = 17 \).

Step 2: Substitute and Simplify the Next Layer

Now substitute the result back into the expression:

  • \( \sqrt{125 + \sqrt{344 + 17}} \)
  • Add the numbers inside the second square root: \( 344 + 17 = 361 \).
  • The expression becomes \( \sqrt{125 + \sqrt{361}} \).

Step 3: Calculate the Second Square Root

Next, calculate the square root of 361:

  • \( \sqrt{361} \)
  • We know that \( 19 \times 19 = 361 \).
  • Therefore, \( \sqrt{361} = 19 \).

Step 4: Substitute and Simplify the Final Layer

Substitute this result back into the expression:

  • \( \sqrt{125 + 19} \)
  • Add the numbers inside the final square root: \( 125 + 19 = 144 \).
  • The expression simplifies to \( \sqrt{144} \).

Step 5: Calculate the Final Square Root

Finally, calculate the square root of 144:

  • \( \sqrt{144} \)
  • We know that \( 12 \times 12 = 144 \).
  • Therefore, \( \sqrt{144} = 12 \).

Final Answer

The value of the expression \( \sqrt{125 + \sqrt{344 + \sqrt{289}}} \) is 12.

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Important Questions from Simplification

  1. The value of {5 - 5 ÷ (10 - 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:

  2. What should come in place of the question mark (?) in the following question?

    [((16 ÷ 4) × 4) ÷ 4] = ?

  3. Simplify the following expression.

    \(\frac{{6\frac{1}{2} + 2\frac{5}{7} \times \frac{{14}}{{19}} - \frac{1}{2} \div 2\ of\frac{1}{4}}}{{11 \times 12 \div 12 + 12}}\)

  4. The value of \(\left( {\frac{7}{5} \div \frac{7}{{10}}of\frac{3}{4}} \right) \div \frac{4}{9} + \left( {\frac{7}{{16}} \div 10\frac{1}{2} \times 7\frac{1}{5}} \right) \times \frac{5}{{12}} \)  is:

  5. The value of \(\left( {{1 \over 2}} \right)\) [{–2(12 + 2)}10] is:

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