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Question

Find the value of m.
$\displaystyle m - \frac{2}{3} = \frac{5}{6} + \frac{1}{2}$

The correct answer is
2

Solving for m: Equation with Fractions

The problem requires finding the value of '$m$' in the given algebraic equation:

$ m - \frac{2}{3} = \frac{5}{6} + \frac{1}{2} $

Step 1: Simplify the Right-Hand Side (RHS)

First, calculate the sum of the fractions on the right side of the equation. Find a common denominator for $\frac{5}{6}$ and $\frac{1}{2}$, which is 6.

  • Convert $\frac{1}{2}$ to an equivalent fraction with a denominator of 6: $ \frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6} $
  • Add the fractions: $ \frac{5}{6} + \frac{3}{6} = \frac{5+3}{6} = \frac{8}{6} $
  • Simplify the resulting fraction: $ \frac{8}{6} = \frac{8 \div 2}{6 \div 2} = \frac{4}{3} $

The equation now becomes:

$ m - \frac{2}{3} = \frac{4}{3} $

Step 2: Isolate m

To find the value of '$m$', add $\frac{2}{3}$ to both sides of the equation:

$ m = \frac{4}{3} + \frac{2}{3} $

Step 3: Calculate the Final Value of m

Add the fractions on the right side:

$ m = \frac{4+2}{3} = \frac{6}{3} $

Simplify the result:

$ m = 2 $

Therefore, the value of '$m$' is 2.

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Important Questions from Quick Math

  1. A is 120% of B and B is 65% of C. If the sum of A, B and C is 121.5, then the value of C - 2B + A is:

  2. A college hostel mess has provisions for 25 days for 350 boys. At the end of 10 days, when some boys were shifted to another hostel, it was found that now the provisions will last for 21 more days. How may boys were shifted to another hostel?
  3. Some students (only boys and girls) from different schools appeared for an Olympiad exam. 20% of the boys and 15% of the girls failed the exam. The number of boys who passed the exam was 70 more than that of the girls who passed the exam. A total of 90 students failed. Find the number of students that appeared for the exam.
  4. The price of an item is reduced by 20%. As a result, customers can get 2 kg more of it for ₹360. Find the original price (in ₹) per kg of the item.

  5. A tyre has 3 punctures. The first puncture alone would have made the tyre flat in 9 minutes, the second alone would have done it in 18 minutes, the third alone would have done it in 6 minutes. If the air leaks out at a constant rate, then how long (in minutes) does it take for all the punctures together to make it flat?

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