Find the value: \((1/3)^{-3}+(1/9)^{-3}+(1/4)^{-3}\)
820
\(3^3+9^3+4^3=27+729+64=820\)
Find the value of $47^{-8} \div 47^3 \times 47^{-19}$.
Given that $58^{0.5} = x$, $58^{0.79}= y$ and $x^z = y^{10}$, then the value of z is close to:
The value of $8^{2} + \sqrt{ 3^{2} } -2 \sqrt{36} -11$ is