Find the standard deviation of the following data (rounded off to two decimal places). 5, 3, 4, 7
The standard deviation is a measure of the amount of variation or dispersion of a set of data points. A low standard deviation indicates that the data points tend to be close to the mean of the set, while a high standard deviation indicates that the data points are spread out over a wider range of values. In this problem, we are asked to find the standard deviation of the data set: 5, 3, 4, 7.
There are slightly different formulas for population standard deviation ($\sigma$) and sample standard deviation ($s$). Based on the options provided and common practice when a small data set is given without context, the calculation often implies the population standard deviation formula or the formula $\sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}$. We will proceed with this interpretation.
To find the standard deviation of the given data, we follow these steps:
The mean ($\mu$) is the sum of all data points divided by the number of data points ($n$).
Data points ($x_i$): 5, 3, 4, 7
Number of data points ($n$): 4
Sum of data points ($\sum x_i$): $5 + 3 + 4 + 7 = 19$
Mean ($\mu$):
$\mu = \frac{\sum x_i}{n} = \frac{19}{4} = 4.75$
The mean of the data is 4.75.
Subtract the mean (4.75) from each data point ($x_i - \mu$).
Square each of the deviations calculated in the previous step ($(x_i - \mu)^2$).
Add up all the squared deviations ($\sum (x_i - \mu)^2$).
Sum of squared deviations = $0.0625 + 3.0625 + 0.5625 + 5.0625 = 8.75$
The variance ($\sigma^2$) is the average of the squared deviations. Using the population variance formula:
$\sigma^2 = \frac{\sum (x_i - \mu)^2}{n}$
$\sigma^2 = \frac{8.75}{4} = 2.1875$
The variance is 2.1875.
The standard deviation ($\sigma$) is the square root of the variance.
$\sigma = \sqrt{\sigma^2} = \sqrt{2.1875}$
Calculating the square root:
$\sigma \approx 1.478935$
We need to round the standard deviation to two decimal places.
$\sigma \approx 1.478935$ rounded to two decimal places is 1.48.
The standard deviation of the data set 5, 3, 4, 7 is approximately 1.48 when rounded to two decimal places.
| $x_i$ | $\mu$ | $x_i - \mu$ | $(x_i - \mu)^2$ |
|---|---|---|---|
| 5 | 4.75 | 0.25 | 0.0625 |
| 3 | 4.75 | -1.75 | 3.0625 |
| 4 | 4.75 | -0.75 | 0.5625 |
| 7 | 4.75 | 2.25 | 5.0625 |
| $\sum x_i = 19$ | $\sum (x_i - \mu) = 0$ | $\sum (x_i - \mu)^2 = 8.75$ |
Variance ($\sigma^2$) = $\frac{8.75}{4} = 2.1875$
Standard Deviation ($\sigma$) = $\sqrt{2.1875} \approx 1.48$
| Concept | Description | Formula (Population) | Formula (Sample) |
|---|---|---|---|
| Mean | The average of the data points. | $\mu = \frac{\sum x_i}{n}$ | $\bar{x} = \frac{\sum x_i}{n}$ |
| Variance | Average of the squared differences from the mean. | $\sigma^2 = \frac{\sum (x_i - \mu)^2}{n}$ | $s^2 = \frac{\sum (x_i - \bar{x})^2}{n-1}$ |
| Standard Deviation | Square root of the variance; measures data dispersion. | $\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{n}}$ | $s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}$ |
The standard deviation is a fundamental statistic used in many fields. Here are some key points about its use:
Calculate the mean from the following table.
Scores | Frequencies |
0-10 | 2 |
10-20 | 4 |
20-30 | 12 |
30-40 | 21 |
40-50 | 6 |
50-60 | 3 |
60-70 | 2 |
If the standard deviation of a population is 5, what will be its variance?
A. 10
B. 15
C. 25
D. 12.5
The variance of a set of data is 196. Then the standard deviation of the data is.
A. ± 14
B. 14
C. 96
D. 98The variance of a set of data is 144. Then the standard deviation of the data is:
A. ±12
B. 12
C. 44
D. 72
The mean of a distribution is 24 and the standard deviation is 6. What is the value of variance coefficient?
A. 50%
B. 25%
C. 100%
D. 75%