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Question

Find the standard deviation of the following data (rounded off to two decimal places).

5, 3, 4, 7

The correct answer is 1.48

Understanding Standard Deviation

The standard deviation is a measure of the amount of variation or dispersion of a set of data points. A low standard deviation indicates that the data points tend to be close to the mean of the set, while a high standard deviation indicates that the data points are spread out over a wider range of values. In this problem, we are asked to find the standard deviation of the data set: 5, 3, 4, 7.

There are slightly different formulas for population standard deviation ($\sigma$) and sample standard deviation ($s$). Based on the options provided and common practice when a small data set is given without context, the calculation often implies the population standard deviation formula or the formula $\sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}$. We will proceed with this interpretation.

Steps to Calculate Standard Deviation

To find the standard deviation of the given data, we follow these steps:

  1. Calculate the mean ($\mu$) of the data.
  2. Find the deviation of each data point from the mean ($x_i - \mu$).
  3. Square each deviation ($(x_i - \mu)^2$).
  4. Sum the squared deviations ($\sum (x_i - \mu)^2$).
  5. Calculate the variance ($\sigma^2$) by dividing the sum of squared deviations by the number of data points ($n$).
  6. Calculate the standard deviation ($\sigma$) by taking the square root of the variance.
  7. Round the result to two decimal places as required.

Step 1: Calculate the Mean

The mean ($\mu$) is the sum of all data points divided by the number of data points ($n$).

Data points ($x_i$): 5, 3, 4, 7

Number of data points ($n$): 4

Sum of data points ($\sum x_i$): $5 + 3 + 4 + 7 = 19$

Mean ($\mu$):

$\mu = \frac{\sum x_i}{n} = \frac{19}{4} = 4.75$

The mean of the data is 4.75.

Step 2: Calculate Deviations from the Mean

Subtract the mean (4.75) from each data point ($x_i - \mu$).

  • $5 - 4.75 = 0.25$
  • $3 - 4.75 = -1.75$
  • $4 - 4.75 = -0.75$
  • $7 - 4.75 = 2.25$

Step 3: Square the Deviations

Square each of the deviations calculated in the previous step ($(x_i - \mu)^2$).

  • $(0.25)^2 = 0.0625$
  • $(-1.75)^2 = 3.0625$
  • $(-0.75)^2 = 0.5625$
  • $(2.25)^2 = 5.0625$

Step 4: Sum the Squared Deviations

Add up all the squared deviations ($\sum (x_i - \mu)^2$).

Sum of squared deviations = $0.0625 + 3.0625 + 0.5625 + 5.0625 = 8.75$

Step 5: Calculate the Variance

The variance ($\sigma^2$) is the average of the squared deviations. Using the population variance formula:

$\sigma^2 = \frac{\sum (x_i - \mu)^2}{n}$

$\sigma^2 = \frac{8.75}{4} = 2.1875$

The variance is 2.1875.

Step 6: Calculate the Standard Deviation

The standard deviation ($\sigma$) is the square root of the variance.

$\sigma = \sqrt{\sigma^2} = \sqrt{2.1875}$

Calculating the square root:

$\sigma \approx 1.478935$

Step 7: Round the Result

We need to round the standard deviation to two decimal places.

$\sigma \approx 1.478935$ rounded to two decimal places is 1.48.

Final Answer Summary

The standard deviation of the data set 5, 3, 4, 7 is approximately 1.48 when rounded to two decimal places.

$x_i$ $\mu$ $x_i - \mu$ $(x_i - \mu)^2$
5 4.75 0.25 0.0625
3 4.75 -1.75 3.0625
4 4.75 -0.75 0.5625
7 4.75 2.25 5.0625
$\sum x_i = 19$ $\sum (x_i - \mu) = 0$ $\sum (x_i - \mu)^2 = 8.75$

Variance ($\sigma^2$) = $\frac{8.75}{4} = 2.1875$

Standard Deviation ($\sigma$) = $\sqrt{2.1875} \approx 1.48$

Revision Table - Key Statistics Concepts

Concept Description Formula (Population) Formula (Sample)
Mean The average of the data points. $\mu = \frac{\sum x_i}{n}$ $\bar{x} = \frac{\sum x_i}{n}$
Variance Average of the squared differences from the mean. $\sigma^2 = \frac{\sum (x_i - \mu)^2}{n}$ $s^2 = \frac{\sum (x_i - \bar{x})^2}{n-1}$
Standard Deviation Square root of the variance; measures data dispersion. $\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{n}}$ $s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}$

Additional Information - Standard Deviation Use

The standard deviation is a fundamental statistic used in many fields. Here are some key points about its use:

  • Data Comparison: It allows comparing the spread of different data sets, even if they have similar means.
  • Quality Control: Used in manufacturing to monitor the consistency of products. A smaller standard deviation indicates less variation and higher quality consistency.
  • Finance: Used to measure the volatility or risk of investments. A higher standard deviation means greater price swings and higher risk.
  • Statistical Inference: It is a key component in many statistical tests and confidence interval calculations.
  • Normal Distribution: For data that follows a normal distribution, about 68% of the data falls within one standard deviation of the mean, about 95% within two standard deviations, and about 99.7% within three standard deviations. This is known as the empirical rule or the 68-95-99.7 rule.
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Important Questions from Standard Deviation

  1. Calculate the mean from the following table.

    Scores

    Frequencies

    0-10

    2

    10-20

    4

    20-30

    12

    30-40

    21

    40-50

    6

    50-60

    3

    60-70

    2

  2. If the standard deviation of a population is 5, what will be its variance?

    A. 10

    B. 15

    C. 25

    D. 12.5

  3. The variance of a set of data is 196. Then the standard deviation of the data is.

    A. ± 14

    B. 14

    C. 96

    D. 98
  4. The variance of a set of data is 144. Then the standard deviation of the data is:

    A. ±12

    B. 12

    C. 44

    D. 72

  5. The mean of a distribution is 24 and the standard deviation is 6. What is the value of variance coefficient?

    A. 50%

    B. 25%

    C. 100%

    D. 75%

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