Calculate the mean from the following table. Scores Frequencies 0-10 2 10-20 4 20-30 12 30-40 21 40-50 6 50-60 3 60-70 2
33.4
To find the mean (average) from a frequency distribution table like the one provided, where data is grouped into class intervals, we follow these steps:
$$\text{Mean} = \frac{\sum f_ix_i}{\sum f_i}$$
Let's apply these steps to the given table of scores and frequencies:
| Scores (Class Interval) | Frequency ($f_i$) | Midpoint ($x_i$) | $f_ix_i$ |
|---|---|---|---|
| 0-10 | 2 | $$\frac{0+10}{2} = 5$$ | $$2 \times 5 = 10$$ |
| 10-20 | 4 | $$\frac{10+20}{2} = 15$$ | $$4 \times 15 = 60$$ |
| 20-30 | 12 | $$\frac{20+30}{2} = 25$$ | $$12 \times 25 = 300$$ |
| 30-40 | 21 | $$\frac{30+40}{2} = 35$$ | $$21 \times 35 = 735$$ |
| 40-50 | 6 | $$\frac{40+50}{2} = 45$$ | $$6 \times 45 = 270$$ |
| 50-60 | 3 | $$\frac{50+60}{2} = 55$$ | $$3 \times 55 = 165$$ |
| 60-70 | 2 | $$\frac{60+70}{2} = 65$$ | $$2 \times 65 = 130$$ |
Now, we calculate the sums:
Using the formula for the mean of grouped data:
$$\text{Mean} = \frac{\sum f_ix_i}{\sum f_i}$$
Substituting the calculated values:
$$\text{Mean} = \frac{1670}{50}$$
$$\text{Mean} = 33.4$$
Therefore, the mean score calculated from the given frequency table is 33.4.
| Term | Definition |
|---|---|
| Frequency | The number of times a particular value or range of values (class interval) appears in a dataset. |
| Frequency Distribution Table | A table that lists scores or class intervals and their corresponding frequencies. |
| Class Interval | A range into which data is grouped in a frequency distribution. E.g., 0-10, 10-20. |
| Midpoint (Class Mark) | The average of the upper and lower limits of a class interval. Used to represent the interval in mean calculation. |
| Mean | The arithmetic average of a dataset. For grouped data, it's the sum of ($f_ix_i$) divided by the sum of frequencies. |
The mean is one of the key measures of central tendency used in statistics to represent the center or typical value of a dataset. Besides the mean, other important measures include:
These measures provide different perspectives on the center of the data distribution. The mean is sensitive to extreme values, while the median is not.
Find the standard deviation of the following data (rounded off to two decimal places).
5, 3, 4, 7
If the standard deviation of a population is 5, what will be its variance?
A. 10
B. 15
C. 25
D. 12.5
The variance of a set of data is 196. Then the standard deviation of the data is.
A. ± 14
B. 14
C. 96
D. 98The variance of a set of data is 144. Then the standard deviation of the data is:
A. ±12
B. 12
C. 44
D. 72
The mean of a distribution is 24 and the standard deviation is 6. What is the value of variance coefficient?
A. 50%
B. 25%
C. 100%
D. 75%