The following table presents data about academic performance of students showing pass percentage (%) and ratio of male to female among passed and failed students of six different colleges A-F in a city. Based on the data in the table, answer the questions: College-wise Academic Performance of StudentsCollege Pass percentage Ratio of Male to Female in pass students Ratio of Male to Female in fail students A 40% 12 ∶ 13 12 ∶ 5 B 55% 5 ∶ 3 11 ∶ 14 C 70% 7 ∶ 5 5 ∶ 3 D 45% 4 ∶ 1 7 ∶ 3 E 50% 2 ∶ 1 1 ∶ 2 F 37.50% 3 ∶ 2 2 ∶ 1
Find the ratio of number of male to female students in D?
The question asks us to find the ratio of the total number of male students to the total number of female students in College D, based on the provided table data. The table gives us the pass percentage and the ratio of male to female students among both passed and failed students for different colleges.
Let's extract the relevant information for College D from the table:
From the pass percentage, we can determine the fail percentage. If 45% of students passed, then 100% - 45% = 55% of students failed.
Let's assume the total number of students in College D is \( T \). While we don't need the exact number, using a variable helps represent the proportions correctly. The final ratio will be independent of the total number of students.
The ratio of Male to Female among passed students is 4 ∶ 1. This means that for every 4 male students who passed, there is 1 female student who passed. The parts in this ratio sum up to \( 4 + 1 = 5 \).
The ratio of Male to Female among failed students is 7 ∶ 3. The parts in this ratio sum up to \( 7 + 3 = 10 \).
The ratio of male to female students is the total number of male students divided by the total number of female students.
\( \text{Ratio} = \frac{\text{Total Male Students}}{\text{Total Female Students}} = \frac{0.745T}{0.255T} \)
The \( T \) cancels out, as expected. We are left with the ratio \( 0.745 : 0.255 \).
To express this ratio as whole numbers, we can multiply both sides by 1000:
\( 0.745 \times 1000 : 0.255 \times 1000 = 745 : 255 \)
Now, we simplify the ratio \( 745 : 255 \) by finding the greatest common divisor (GCD). Both numbers end in 5, so they are divisible by 5.
So, the simplified ratio is \( 149 : 51 \).
We should check if 149 and 51 have any common factors other than 1. 51 is \( 3 \times 17 \). We can check if 149 is divisible by 3 or 17. The sum of digits of 149 is \( 1+4+9 = 14 \), which is not divisible by 3, so 149 is not divisible by 3. \( 17 \times 8 = 136 \), \( 17 \times 9 = 153 \). So, 149 is not divisible by 17. Thus, 149 and 51 are coprime, and the ratio \( 149 : 51 \) is in its simplest form.
The ratio of the number of male students to the number of female students in College D is \( 149 : 51 \).
| Category | Percentage of Total Students | Male ∶ Female Ratio | Proportion of Male Students | Proportion of Female Students |
|---|---|---|---|---|
| Passed | 45% (0.45T) | 4 ∶ 1 (Total 5 parts) | \( \frac{4}{5} \times 0.45T = 0.36T \) | \( \frac{1}{5} \times 0.45T = 0.09T \) |
| Failed | 55% (0.55T) | 7 ∶ 3 (Total 10 parts) | \( \frac{7}{10} \times 0.55T = 0.385T \) | \( \frac{3}{10} \times 0.55T = 0.165T \) |
| Total | 100% (T) | \( 0.36T + 0.385T = 0.745T \) | \( 0.09T + 0.165T = 0.255T \) |
The total male to female ratio is \( 0.745T : 0.255T \), which simplifies to \( 149 : 51 \).
Data interpretation questions often involve combining information presented in different formats, such as percentages and ratios. To solve such problems effectively:
These techniques are fundamental for solving data interpretation questions involving population distributions, survey results, financial statements, and academic performance data like the one presented here.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?