Find the missing group of letters in the following series:
BC, FGH, LMNO, ____________
The given series consists of groups of consecutive letters: BC, FGH, LMNO.
First, let's observe the length of each group in the series:
The number of letters in each group is increasing by 1. Therefore, the missing group should contain 5 letters.
Next, let's examine the starting letter of each group and its position in the alphabet:
We look at the difference between the positions of the starting letters:
The differences are 4 and 6. This sequence of differences (4, 6) is increasing by 2. The next difference in this pattern should be $6 + 2 = 8$.
To find the starting letter of the missing group, we add the next difference (8) to the position of the last starting letter (L, which is 12):
The 20th letter of the alphabet is T.
Since the missing group must have 5 letters (as determined earlier) and starts with T, the group is formed by the next 5 consecutive letters starting from T:
Thus, the missing group of letters is TUVWX.
The following figures show three curves generated using an iterative algorithm. The total length of the curve generated after 'Iteration n' is:
Note: The figures shown are representative.
Let $a_0 = 0$ and define $a_n = \frac{1}{2}(1 + a_{n-1})$ for all positive integers $n \ge 1$.
The least value of $n$ for which $|1 - a_n| < \frac{1}{2^{10}}$ is __________.
(Answer in integer)
The sum of the first $n$ terms in the sequence 8, 88, 888, 8888, ... is______.