Find the LCM of ab²c², a²bc and a³b³c².
a³b³c²
To find the Least Common Multiple (LCM) of algebraic expressions, we need to identify all the unique prime factors (variables in this case) present in the expressions and take the highest power of each factor.
Let's break down the given expressions:
Now, let's identify the unique variables and their highest powers across all the expressions:
The LCM is found by multiplying the highest powers of all the unique variables together.
LCM $= (\text{Highest power of a}) \cdot (\text{Highest power of b}) \cdot (\text{Highest power of c})$
LCM $= a^3 \cdot b^3 \cdot c^2$
So, the LCM of $ab^2c^2$, $a^2bc$, and $a^3b^3c^2$ is $a^3b^3c^2$.
| Expression | Factors with Powers |
|---|---|
| $ab^2c^2$ | $a^1$, $b^2$, $c^2$ |
| $a^2bc$ | $a^2$, $b^1$, $c^1$ |
| $a^3b^3c^2$ | $a^3$, $b^3$, $c^2$ |
| Highest Power for each variable | $a^3$, $b^3$, $c^2$ |
| LCM | $a^3b^3c^2$ |
It is useful to compare the process of finding LCM with finding the Highest Common Factor (HCF) of algebraic expressions.
For the given expressions $ab^2c^2$, $a^2bc$, and $a^3b^3c^2$:
So, the HCF of $ab^2c^2$, $a^2bc$, and $a^3b^3c^2$ would be $a^1b^1c^1 = abc$. This is different from the LCM.
Understanding the distinction between using the highest power for LCM and the lowest power for HCF is key when working with algebraic expressions.
The greatest three-digit number which is divisible by 14, 28, and 42 is:
What is the greatest number that will divide 209 and 347 leaving remainder 5 and 7 respectively?
A number is three times another number and their HCF is 8. What is the sum of the squares of the numbers?
The HCF of 2091, 3485 and 4879 is x. The sum of the digits of x is:
If three numbers are in ratio of 3 : 5 : 7 and their LCM is 2415, what is the difference between the second number and the first number?