The Least Common Multiple (LCM) is the smallest positive integer that is divisible by each of the given numbers.
We can find the LCM using the prime factorization method:
The unique prime factors are 2, 3, and 5.
LCM = $2^3 \times 3^1 \times 5^1 = 8 \times 3 \times 5 = 120$.
Therefore, the LCM of 8, 12, and 20 is 120.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?