The Least Common Multiple (LCM) is the smallest positive integer that is divisible by each of the given numbers.
We can find the LCM using the prime factorization method:
The unique prime factors are 2, 3, and 5.
LCM = $2^3 \times 3^1 \times 5^1 = 8 \times 3 \times 5 = 120$.
Therefore, the LCM of 8, 12, and 20 is 120.
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?