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Find the lattice parameter '$a$' for a simple cubic crystal refracting an X Ray ($\lambda = 1.54$ $\text{\AA}$) at an angle $45^\circ$ from a plane having miller indices (1, 1, 0) at order (n= 1).

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
1.54 $\text{\AA}$

To determine the lattice parameter \(a\) for a simple cubic crystal, we use Bragg's Law, which gives the condition for constructive interference from crystal planes. The law is expressed as:

\(n\lambda = 2d\sin\theta\)

Where:

  • \(n\) is the order of reflection,
  • \(λ\) is the wavelength of the X-ray,
  • \(d\) is the interplanar spacing,
  • \(θ\) is the angle of incidence (in this case, \(45^\circ\)).

For simple cubic crystals, the interplanar spacing \(d\) for the plane with Miller indices (hkl) is given by:

\(d = \frac{a}{\sqrt{h^2 + k^2 + l^2}}\)

For the (110) plane, \(h = 1\)\(k = 1\), and \(l = 0\), thus:

\(d = \frac{a}{\sqrt{1^2 + 1^2 + 0^2}} = \frac{a}{\sqrt{2}}\)

Inserting \(d\) into Bragg's equation:

\(n\lambda = 2\left(\frac{a}{\sqrt{2}}\right)\sin\theta\)

Given that \(n = 1\) and \(θ = 45^\circ\), we know: \(\sin 45^\circ = \frac{\sqrt{2}}{2}\)

Thus, the equation simplifies to:

\(\lambda = \sqrt{2}a \cdot \frac{\sqrt{2}}{2}\)

\(\lambda = a\)

Given \(\lambda = 1.54 \ \text{Å}\), it follows that \(a = 1.54 \ \text{Å}\).

Therefore, the lattice parameter \(a\) is 1.54 Å.

The correct answer is: 1.54 Å.

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