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Question

Find the highest common factor (HCF) of the two numbers 64 and 148.

The correct answer is
4

Finding HCF of 64 and 148

The Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), is the largest number that divides two or more numbers without leaving a remainder.

We can find the HCF of 64 and 148 using the prime factorization method:

  • Step 1: Prime Factorization
    • Find the prime factors of 64: $64 = 2 \times 32 = 2 \times 2 \times 16 = 2 \times 2 \times 2 \times 8 = 2 \times 2 \times 2 \times 2 \times 4 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^6$
    • Find the prime factors of 148: $148 = 2 \times 74 = 2 \times 2 \times 37 = 2^2 \times 37$
  • Step 2: Identify Common Factors
    • The prime factors of 64 are: $2, 2, 2, 2, 2, 2$.
    • The prime factors of 148 are: $2, 2, 37$.
    • The common prime factors are $2$ and $2$.
  • Step 3: Calculate HCF
    • Multiply the common prime factors.
    • $HCF = 2 \times 2 = 4$.

Alternatively, using the Euclidean Algorithm:

  • Divide 148 by 64: $148 = 2 \times 64 + 20$
  • Divide 64 by the remainder 20: $64 = 3 \times 20 + 4$
  • Divide 20 by the remainder 4: $20 = 5 \times 4 + 0$
  • The last non-zero remainder is the HCF. In this case, it is 4.

Therefore, the highest common factor of 64 and 148 is 4.

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Important Questions from LCM and HCF

  1. Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?

  2. A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:

  3. Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

  4. Calculate the HCF of \(\frac{12}{5}\) \(\frac{14}{15}\)  and  \(\frac{16}{17}\) .

  5. Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?

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