Find the area of the triangle whose height is 56 cm and the corresponding base is 1/4th of the height.
392 cm2
The question asks us to find the area of a triangle given its height and the relationship of its base to the height.
The base is given as $\frac{1}{4}$ of the height. We can calculate the base by multiplying the height by $\frac{1}{4}$.
Base = $\frac{1}{4} \times \text{Height}$
Base = $\frac{1}{4} \times 56 \text{ cm}$
To calculate this, we can divide 56 by 4.
$$ \text{Base} = \frac{56}{4} \text{ cm} $$ $$ \text{Base} = 14 \text{ cm} $$So, the base of the triangle is 14 cm.
The formula for the area of a triangle is:
$$ \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} $$Now, we substitute the values we know:
We can simplify the calculation:
$$ \text{Area} = ( \frac{1}{2} \times 14 ) \times 56 \text{ cm}^2 $$ $$ \text{Area} = 7 \times 56 \text{ cm}^2 $$Now, we multiply 7 by 56:
$$ 7 \times 56 = 7 \times (50 + 6) $$ $$ = (7 \times 50) + (7 \times 6) $$ $$ = 350 + 42 $$ $$ = 392 $$So, the area of the triangle is 392 cm$^2$.
The area of the triangle with a height of 56 cm and a base $\frac{1}{4}\text{th}$ of the height is 392 cm$^2$.
| Measurement | Value |
|---|---|
| Height | 56 cm |
| Base (calculated) | 14 cm |
| Area (calculated) | 392 cm$^2$ |
| Concept | Description | Formula (if applicable) |
|---|---|---|
| Triangle | A polygon with three sides and three angles. | - |
| Base | Any side of the triangle chosen as the base for area calculation. | - |
| Height (Altitude) | The perpendicular distance from the opposite vertex to the base (or the extension of the base). | - |
| Area of Triangle | The measure of the space enclosed by the triangle. | $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$ |
Triangles can be classified based on their sides or angles.
The formula for the area ($\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$) works for all types of triangles, as long as the correct corresponding base and height are used.
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